assignment between const char and char

Asked Jul 01 '14 at 09:07

Active Jul 01 '14 at 09:35

Viewed 67 times

I am confused about the assignment between the two. Look at the follow code.

char **argv;
const char**p = argv;   // compile error

char * cp;
const char * ccp = cp;  // no compile error

But the question one of the similar question may have some conflicts with mine. He can compile with the above code. problem: how do I understand the assignment?

edited May 23 '17 at 10:26

Community

asked Jul 01 '14 at 09:07

kkwang

Why did you tag the question C? – David Heffernan Jul 01 '14 at 09:08
2

@DavidHeffernan Why is it explicitly C++? Because of the unnecessary `#include ` line? – Csq Jul 01 '14 at 09:10
@Csq Well, that does make this C++ and not C. But maybe I over-reacted. – David Heffernan Jul 01 '14 at 09:11
2

See here too: http://www.parashift.com/c++-faq-lite/constptrptr-conversion.html – David Heffernan Jul 01 '14 at 09:13
@DavidHeffernan Thanks. It should be C code originally. And thank you for your link. It helps. – kkwang Jul 01 '14 at 09:34

assignment between const char** and char**

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assignment between const char and char