parse template tag to XML in Django

Question

I am trying to print get some value from database and print into xml dynamically.

This is my model:

class Somemodel(models.Model):
    Party_Id = models.CharField(max_length=500)
    Label = models.CharField(max_length=500)
    Party_Id = models.CharField(max_length=500)
    Name = models.CharField(max_length=500)

This is my view function

def xmlcontent(request):
  obj = Somemodel.objects.get(pk=1)
  obj.Party_Id = obj.pk
  pprint.pprint(obj.DDEX_Party_Id)
  return render(request, "content.xml", {"DDID": "obj"},
content_type =   "application/xhtml+xml")

My content.xml looks like this

<?xml version="1.0" encoding="UTF-8"?><br/>
<</MessageHeader>MessageHeader><br/>
    {% for i in DDID %}<br/>
        {{ i.pk }}<br/>
    {% endfor %} <br/>
<</MessageHeader>/MessageHeader><br/>

Its suppose to print Party_id but not printing.. Am i miss something ?

Burhan Khalid · Accepted Answer · 2014-07-01T09:20:56.557

A few problems:

You are sending the string "obj" instead of the object obj in your context dictionary.
In your xml template, you have a loop, but the context variable DDID is going to be a single object, not a collection or queryset, because you are using .get.
You have extra < in your XML, and XML does not include <br /> tags. The resulting file will be invalid.

To save yourself some trouble, just use the built-in serializers. The first example shows you how to export XML:

from django.core import serializers

def some_method(request):
    XMLSerializer = serializers.get_serializer("xml")
    xml_serializer = XMLSerializer()
    xml_serializer.serialize(SomeModel.objects.filter(pk=1).values('id'), stream=request)

for intent only i give
tag . I changed into obj gives nothing. You mentioned serializer i tried but using that i can able to get all the database into xml format. But i need particular value from db to print. I don`t have much exp to use serializer to get what i need this point — Raja Simon, Jul 01 '14 at 09:17

score 0 · Answer 2 · answered Jul 01 '14 at 08:59

0

With this line

return render(request, "content.xml", {"DDID": "obj"},

you are passing string "obj" to template rather than the obj object. Update it to

return render(request, "content.xml", {"DDID": obj},

Also obj is not a list but single object, so you cannot use {%for i in DDID %} ...

answered Jul 01 '14 at 08:59

Rohan

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I changed into {{ pk }} . Thats gives me no output – Raja Simon Jul 01 '14 at 09:05
@rajasimon You need to do `{{DDID.pk}}`. – Rohan Jul 01 '14 at 09:11
Changed inot {{ DDID }} give value 1 but i know that`s not correct. And then i changed this line into obj = Somemodel.objects.get(Party_Id).. Gives Exceptn 'too many values to unpack' – Raja Simon Jul 01 '14 at 09:13
pprint.pprint(obj) gives this output ([{'Party_Id': u'112'}],) but i need that value come into xml ...? – Raja Simon Jul 01 '14 at 09:54

parse template tag to XML in Django

2 Answers2