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Adding UInt64 in array without "( )" gives unexpected value

    var arr : Any[] = []
    var no : UInt64 = 9971989999
    arr.append(no)
    println(arr)

While with "( )" gives correct value

    var arr : Any[] = []
    var no : UInt64 = 9971989999
    arr.append("\(no)")
    println(arr)

Why?

Rachit
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    I'm not sure it will affect the code but using names like `no` for an integer is confusing as hell to read. Also, what is your output for the two `println` statements? You've told us it doesn't work but you haven't said what it is doing. – Fogmeister Jun 30 '14 at 13:33
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    Either I need to take a far closer look at Swift or those two snippets do entirely different things (the first appends the value of the integer called `no`, the second appends a string that happens to look similar to the variable name `no` if you squint). Please clarify your question, for example by giving the expected and actual output. –  Jun 30 '14 at 13:35
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    @delnan Ah yes, the syntax `"\(var)"` uses the String parsing to create a string from the variable. – Fogmeister Jun 30 '14 at 13:38
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    Your code produces the correct result `[9971989999]` when I compile and run it in a 64-bit iOS Simulator. In a 32-bit Simulator I get `[237764688]` as output. So this looks like (another) bug in the Swift compiler or runtime. – Martin R Jun 30 '14 at 13:44
  • Any chance of actually putting the unexpected value in the question? – JeremyP Jun 30 '14 at 16:03
  • @MartinR seems to have found the key issue here. Be sure to [file a bug](http://bugreport.apple.com) so Apple can fix it — you can probably help by testing on 32 vs 64 bit devices to note whether it's a device or simulator issue. – rickster Jun 30 '14 at 16:33

1 Answers1

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I think Its a Swift bug. You can report it to Apple. Its Working in 64-bit iOS but not in 32-bit iOS.

Generally there is no need to change println(arr) into println("\(arr)") for printing such values and You convert int into string by use of "\()" while saving to array.

Rachit
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Mohit Jethwa
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