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The following Scala code does just what I expect it to - it prints each line of some_file.txt. 

import scala.io.Source
val lines = Source.fromPath("some_file.txt").mkString
for (line <- lines) print(line)

If I use println instead of print, I expect to see some_file.txt printed out with double-spacing. Instead, the program prints a newline after every character of some_file.txt. Could someone explain this to me? I'm using Scala 2.8.0 Beta 1.

user293361
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2 Answers2

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lines is a single string, not some iterable container of strings. This is because you called the .mkString method on it.

When you iterate over a string, you do so one character at a time. So the line in your for is not actually a line, it's a single character.

What you probably intended to do was call .getLines instead of .mkString

Ben James
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  • He called `.mkString` on the result of `fromPath`, which is an `Iterator[Char]` with some added stuff. I know you know this, but I think you could make it clearer. You could also put an example of a for comprehension over a `String` literal. – Daniel C. Sobral Mar 14 '10 at 19:46
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I suspect that for (line <- lines) print(line) doesn't put a line in line but instead a character. Making the output as expected since the \n is there too. When you the replace the print with println every character gets its own line.

ase
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