How to split string using a whole word as separator?

Question

Is there a way to split string like:

"importanttext1 has gathered importanttext2 from stackoverflow."

I want to grab anything before the word "has", and just want to grab the one word after "gathered", so it doesn't include "from stackoverflow.". I want to be left with 2 variables that cointain importanttext1 and importanttext2

You mean: get the word before `has` and the word after `gathered`? I don't get it. And show what you have tried. — Yu Hao, Jun 25 '14 at 13:11
I imagine Lua's regex would suffice for something like this, but your question is still unclear. Please elaborate. — Stratus3D, Jun 25 '14 at 13:14

score 1 · Accepted Answer · answered Jun 25 '14 at 13:52

1

local str = "importanttext1 has gathered importanttext2 from stackoverflow."
local s1 = str:match("(.+)has")
local s2 = str:match("gathered%s+(%S+)")
print(s1)
print(s2)

Note that "%s" matches a whitespace character while "%S" matches a non-whitespace character.

answered Jun 25 '14 at 13:52

Yu Hao

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what about: `local s1,s2 = str:match'(.+)%s+has gathered%s+(.+)%s+from'`? would be faster I think – nonchip Jun 27 '14 at 14:40

How to split string using a whole word as separator?

1 Answers1