How to replace each letters in multiple words

Question

I have an array like this :

input =  ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine" "thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"]

i would like output = ["thirty", "forty", "sixty", "seventy", "eighty", "ninety"]

import re 
chaine = ["thirtheen", "fourteen", "fifteen"] 
print re.sub(r'[een]', 'y', ' '.join(chaine))

I try a lot of method (replace .. ) but i am stuck :/

Have you had a go with the method? Show us your attempts. Also what language are you using? — AndrewPolland, Jun 20 '14 at 16:06
Your question doesn't make sense. would you like `one -> ony` and `four -> for` ? — Nir Alfasi, Jun 20 '14 at 16:08
You don't need regular expressions for this. A simple `' '.join(chaine).replace('een', 'y')` does the job. Your regex `[een]` matches exactly one of e or n. — Jasper, Jun 20 '14 at 16:18
@jasper , yes but i would like something like : chaine = ["thirtheen", "fourteen", "fifteen"] print ' '.join(chaine).replace('een', 'y', 'our', 'o') — newuser, Jun 20 '14 at 16:20
Then please update your answer to state exactly what output you want from which input you have. — Jasper, Jun 20 '14 at 16:22

score 1 · Accepted Answer · answered Jun 20 '14 at 16:23

1

This will help you.

chain = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"] 


new_chain = []

for _ in chain:
    if _ == "fourteen":
        new_chain.append("forty")
    elif str.endswith(_,"een"):
        new_chain.append(_[:-3]+"y")
print new_chain

OUTPUT:

['thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']

answered Jun 20 '14 at 16:23

DOSHI

442
2
23

1

use `str.endswith()` instead of `[-3:]` – Jasper Jun 20 '14 at 16:26
1

Thank you, just edited. Your suggestion was helpful. Upvoted your comment. – DOSHI Jun 20 '14 at 16:29
1

@newuser. You may tick mark my solution, if you find it useful. Thanks – DOSHI Jun 20 '14 at 16:35
Your response is useful but i wait other solutions ^^ – newuser Jun 20 '14 at 16:38

How to replace each letters in multiple words

1 Answers1