Selenium assert has class

Question

I have an element with a known id. I want to assert or verify that it has a specific class.

The HTML of the element is:

<a id="SearchList" class="something-else disabled"></a>

I want to use the id "SearchList" to locate the element and then verify that it has the class "disabled".

EDITS:

I am using the Selenium IDE a FireFox addon.

score 7 · Accepted Answer · answered Jun 20 '14 at 17:35

7

verifyElementPresent | css=a[id='SearchList'][class*='disabled'] |

answered Jun 20 '14 at 17:35

ism

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doesn't the IDE support `css=#SearchList.disabled` ? – Matthijs Wessels Jun 08 '16 at 10:54

AlignedDev · Answer 2 · 2016-06-08T14:48:29.807

3

This doesn't help you for the IED, but in C# I can do this using the GetAttribute method.

var allClasses = webElement.GetAttribute("class");
var elementHasClass = allClasses.Split(' ').Any(c => string.Equals("classLookingFor", c, StringComparison.CurrentCultureIgnoreCase));

edited Jun 08 '16 at 14:48

answered Nov 20 '15 at 17:04

AlignedDev

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@MatthijsWessels yep, that is redundant. I'll edit my answer – AlignedDev Jun 08 '16 at 14:48

score -1 · Answer 3 · answered Jun 19 '14 at 15:51

-1

You could use getAttribute() method to get the attribute and verify that. I assume you use Java for your scripts.

WebElement list = driver.findElement(By.id("SearchList"));
String disabled = list.getAttribute("disabled");

if(disabled.equals("disabled")){
  // something
}else{
  // something else
}

answered Jun 19 '14 at 15:51

Purus

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I am using the Selenium IDE for FireFox. – ism Jun 19 '14 at 15:57
The question was not if the element has the attribute "disabled" set, it was about whether the element has the class "disabled" – Matthijs Wessels Jun 08 '16 at 15:01

score -1 · Answer 4 · answered Apr 08 '16 at 12:00

-1

Sorry for necroposting. I have some addition to what @Purus suggested.

As "disabled" is part of a class name class="something-else disabled", list.getAttribute("disabled") will return null. My suggestion to do it in the following way (Selenium WebDriver Java client):

WebElement element= driver.findElement(By.id("SearchList"));
String elementClass= element.getAttribute("class");

if(elementClass != null && elementClass.contains("disabled")){
  // something
}else{
  // something else
}

answered Apr 08 '16 at 12:00

Dragon

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this would pass with class="not-disabled". Just port Aligned's solution to Java if you want java. – Matthijs Wessels Jun 08 '16 at 10:53
Yes, it would pass "not-disabled", but TS asked to locate concrete class that is "disabled" and not "not-disabled". – Dragon Jun 08 '16 at 14:12
Let me reword: he wants to verify if the element has the class "disabled". If the element has any class that contains the text "disabled" (e.g. "not-disabled"), your code would act as if it has the class "disabled". This is wrong. – Matthijs Wessels Jun 08 '16 at 14:59

Selenium assert has class

4 Answers4