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I'm studying the behavior of the branch and bound algorithm in a integer 2-variable linear problem. I occasionally use Wolfram Alpha for plotting graphs, but now I need a more robust option, Mathematica. I need to plot the viable zone of a set of inequalities on the R2 space (with x and y greater than 0), inequalities such as:

2*x+4*y <= 12 // 6*x+2*y <= 27 // x <= 4 // x>=0 // y>=0

The graph must show all integer x,y points on the positive quadrant (I think a mesh function can do this) and a specific point (solution of the max/minimization problem) For example, the viable space in this case is: http://www.wolframalpha.com/input/?i=plot%282*x%2B4*y%3C%3D12%2C6*x%2B2*y%3C%3D27%2Cx%3C%3D4%2Cx%3E%3D0%2Cy%3E%3D0%29

thanks in advance.

alfablac
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  • Welcome to SO. This question is not in a format suitable for the site. It is too general. Can you show what you have tried? What errors are you getting? – dcarson Jun 18 '14 at 01:56

1 Answers1

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The function you are looking for is RegionPlot:

RegionPlot[
 2 x + 4 y <= 12 && 6 x + 2 y <= 27 && x <= 4 && x >= 0 && y >= 0, {x,
   0, 5}, {y, 0, 5}]

enter image description here

To make a nice-looking plot over the integer points the inequality satisfies, here is a function to plot it:

IntegerRegionPlot[quantifier_, {xmin_, xmax_}, {ymin_, ymax_}] := 
  Graphics[Flatten[
    Table[If[
      quantifier, {Red, Disk[{x, y}, 0.5]}, {Blue, 
       Disk[{x, y}, 0.5]}], {x, xmin, xmax}, {y, ymin, ymax}]], 
   Frame -> True];

To plot the inequality, just do this:

IntegerRegionPlot[
 2 x + 4 y <= 12 && 6 x + 2 y <= 27 && x <= 4 && x >= 0 && y >= 0, {0,
   5}, {0, 5}]

enter image description here

DumpsterDoofus
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