Concatenate mixed types for println

Question

I am trying to concatenate a string and an integer, and log to the console using println.

println("Load number: " + webViewLoads)

webViewLoads is type 'Int'. As I'm mixing two types here, there is no surprise that I'm getting an error:
Could not find an overload for 'println' that accepts the supplied arguments.

So, I tried casting webViewLoads as a string: println("Load: " + webViewLoads as String)

Grr.. Error still thrown.

How can I make this simple little concatenation work?

possible duplicate of [Append String in Swift](http://stackoverflow.com/questions/24180346/append-string-in-swift) — PREMKUMAR, Jun 12 '14 at 15:54
Also `println("Load: " + (webViewLoads as String))` should work — Eduardo, Jun 12 '14 at 16:06

score 22 · Accepted Answer · answered Jun 12 '14 at 15:48

22

You have a couple of options. You can create a new String from the Int and concatenate it, or you can use string interpolation.

println("Load number: " + String(webViewLoads))
println("Load number: \(webViewLoads)")

answered Jun 12 '14 at 15:48

Mick MacCallum

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PREMKUMAR · Answer 2 · 2014-06-12T16:07:30.510

0

Check below code:

let string1 = "This is"
let intValue = 45
var appendString = "\(string1) \(intValue)"
println("APPEND STRING:\(appendString)")

edited Jun 12 '14 at 16:07

answered Jun 12 '14 at 15:50

PREMKUMAR

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1

He is asking how to append an Int to a String. You are showing two Strings. For the same reason, it is not a duplicate of the other question you mention in the comments. – Eduardo Jun 12 '14 at 16:05

score 0 · Answer 3 · answered Jun 28 '15 at 18:47

0

I don't think this was mentioned, but this worked for me:

println("Frame Width: " + String(stringInterpolationSegment: frameWidth))

(frameWidth is: var frameWidth = self.frame.width)

answered Jun 28 '15 at 18:47

Greg A

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Concatenate mixed types for println

3 Answers3