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I have an existing eml file which contain among others body and attachments.

I simply want to add attachments to this file, not erase existing onlt to add attachments.

I have this code to create eml:

public static void createMessage(String to, String from, String subject, String body, List<File> attachments) {
try {
    Message message = new MimeMessage(Session.getInstance(System.getProperties()));
    message.setFrom(new InternetAddress(from));
    message.setRecipients(Message.RecipientType.TO, InternetAddress.parse(to));
    message.setSubject(subject);
    // create the message part 
    MimeBodyPart content = new MimeBodyPart();
    // fill message
    content.setText(body);
    Multipart multipart = new MimeMultipart();
    multipart.addBodyPart(content);
    // add attachments
    for(File file : attachments) {
        MimeBodyPart attachment = new MimeBodyPart();
        DataSource source = new FileDataSource(file);
        attachment.setDataHandler(new DataHandler(source));
        attachment.setFileName(file.getName());
        multipart.addBodyPart(attachment);
    }
    // integration
    message.setContent(multipart);
    // store file
    message.writeTo(new FileOutputStream(new File("c:/mail.eml")));
} catch (MessagingException ex) {
    Logger.getLogger(Mailkit.class.getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
    Logger.getLogger(Mailkit.class.getName()).log(Level.SEVERE, null, ex);
}

}

But how do i add to existing rather then create?

Michael A
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1 Answers1

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public static void addAttachment(Message msg, File attachment) throws Exception {
    //Create the new body part and add the file
    MimeBodyPart attachment = new MimeBodyPart();
    DataSource source = new FileDataSource(file);
    attachment.setDataHandler(new DataHandler(source));
    attachment.setFileName(file.getName());

    //Add the new body part to the e-mail
    msg.getContent().addBodyPart(attachment);
}

In the above method, a new bodypart is created with the attachment, and that bodypart is then added to the multipart of the e-mail which is already there.

jluckin
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  • That assumes the existing eml file is always and only a message with a single multipart. And you'll need a cast in there for the result of getContent() to cast it to a Multipart. – Bill Shannon Jun 11 '14 at 20:30