trying to achieve an automatic open -> close in tkinter

Question

so i'm doing a project for school with tkinter what i'm currently trying to do is display an image that is a 450x450px .gif

what it needs to do is open > 20sec delay > close

here is the current code

    photo = tkinter.PhotoImage(file = './Images/img1.gif')
    root.geometry("450x450")
    root.update()
    canvas.create_image(225,225, image=photo)
    root.mainloop()

https://i.stack.imgur.com/PSCce.png is the current result

i mean to close the image, but `canvas.destroy()` won't work — Photonium, Jun 09 '14 at 14:50

score 1 · Accepted Answer · answered Jun 09 '14 at 14:53

1

Save the return value of the create_image (item id), then use that value when you delete the image using canvas.delete.

photo = tkinter.PhotoImage(file = './Images/img1.gif')
root.geometry("450x450")
root.update()
img = canvas.create_image(225,225, image=photo)
root.after(20000, lambda: canvas.delete(img)) # 20,000 milli seconds = 20 seconds
root.mainloop()

Using after, you can do some stuff after specified time.

answered Jun 09 '14 at 14:53

falsetru

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Thanks! this solves half the problem, i just need to find out how to display the whole image and not that bit of it. – Photonium Jun 09 '14 at 15:24
@Photonium, I don't understand the last sentence. – falsetru Jun 09 '14 at 15:25
check the image link in the OP, you'll see what i mean – Photonium Jun 09 '14 at 17:26
@Photonium, Do you mean this? http://pastebin.com/DxSrYRQA or http://pastebin.com/1hgZ5uZS – falsetru Jun 09 '14 at 23:16
actually, since this solves the stated problem, im going to just create a new question since i'm trying to solve what i didn't ask for. – Photonium Jun 10 '14 at 01:19

trying to achieve an automatic open -> close in tkinter

1 Answers1