Return value of non-initialized reference_wrapper

Question

Where does reference_wrapper point to when I resize() the vector below? Is this an undefined behavior? What should I do for safety?

std::vector < std::reference_wrapper <int> > vec;
vec.resize(10);

It seems that you can't resize `vec`. You can only `push_back` to add more items to it. — R Sahu, Jun 05 '14 at 21:16

score 5 · Accepted Answer · answered Jun 05 '14 at 21:02

5

Your code doesn't compile, because reference_wrapper doesn't have a default constructor.

error: no matching function for call to ‘std::reference_wrapper<int>::reference_wrapper()’

answered Jun 05 '14 at 21:02

ecatmur

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score 1 · Answer 2 · answered Jun 05 '14 at 21:25

vector<T>::resize(size_type) requires that the T be default constructible, and reference_wrapper isn't, so your code doesn't compile as is.

But presumably, you're asking what happens to the reference_wrapper objects when the vector reallocates storage as necessary. Nothing special, they will continue referring to the object they were originally referring to.

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Return value of non-initialized reference_wrapper

2 Answers2