psutil - getting process name is blank

Question

I'm trying to run this code and I'm not getting the list of processes by name:

import psutil

PROCNAME = "python.exe"

for proc in psutil.process_iter():
    if proc.name == PROCNAME:
        print proc

What I get is nothing even though the process is running.

This is not really a question. You should just try to print out the process names and see what's happening. If it's a bug, report it to psutil bug tracker. If there's something you can't explain, ask on the psutil list. In this case, I think the process name is something like `C:\Python27\python.exe` (or something similar). — Noufal Ibrahim, Jun 02 '14 at 10:03

score 6 · Answer 1 · answered Aug 27 '15 at 16:28

6

I was experiencing the same problem. Changing proc.name to proc.name() solved it for me if anyone else was having similar issues.

answered Aug 27 '15 at 16:28

Joules

1

thank you, instead of documentation, that how it is really works. Because `name` returns object, and `_name` is filled with delay, and usually has state `None`. And just `name()` acts as expected. – Arkady Dec 08 '15 at 09:27

score 3 · Answer 2 · answered Sep 11 '16 at 21:14

3

There have been significant changes in the psutil API with version 2.0.0:

The proc.name class property was replaced by the proc.name() method. So you need to adapt this.

answered Sep 11 '16 at 21:14

romor

score -1 · Answer 3 · answered Jun 02 '14 at 09:50

-1

Try to see exactly which is the format of the process name served by psutil:

import psutil

for proc in psutil.process_iter():
    print proc.name

answered Jun 02 '14 at 09:50

user1202136

3 Answers3