Why Can't I Use istream_iterators in a vector Ctor?

Question

I want to do this:

std::istringstream foo( "13 14 15 16 17 18 19 20" );
std::vector<int> bar( std::istream_iterator<int>( bytes ), std::istream_iterator<int>() );

But rather than recognizing it as the vector range ctor, the compiler thinks that I'm prototyping a function.

Is there a way that I can hint to the compiler what's going on?

You should post some real code. – juanchopanza May 29 '14 at 12:44 — juanchopanza, May 29 '14 at 12:44
The construction of 'foo' is plain wrong – May 29 '14 at 12:44 — , May 29 '14 at 12:44
Fixed `foo` construction – Jonathan Mee May 29 '14 at 12:49 — Jonathan Mee, May 29 '14 at 12:49
Not quite, `std::vector` is not a type. – juanchopanza May 29 '14 at 12:52 — juanchopanza, May 29 '14 at 12:52
Now: Make it 'std::vector bar' and be happy – May 29 '14 at 12:54 — , May 29 '14 at 12:54

Paul · Accepted Answer · 2014-05-29T12:47:10.777

1

If your compiler supports C++11 and uniform initialization you may do

std::vector<int> bar{ std::istream_iterator<int>( bytes ), std::istream_iterator<int>() };

If not, then change to

std::vector bar = std::vector<int>( std::istream_iterator<int>( bytes ), std::istream_iterator<int>() );

Read more about variable initialization vs function declaration ambiguity on Sutter's Mill.

edited May 29 '14 at 12:47

answered May 29 '14 at 12:42

Paul

1 Answers1