javac gives no warning when a class with default access contains public members

Question

Regarding the example code below, although the Test() constructor inside the class Test is public, the class Test itself isn't public, and so the Test() constructor can't be called from outside its own package.

Does that make the public keyword redundant? If so, I wonder why javac doesn't issue a warning about the redundant use of public, when used inside a class whose access is implicitly declared as default ("package private")?

Test.java, package test -

package test;
class Test {
    public Test() {}
}

Main.java, package main -

package main;
class Main {
    public static void main(String[] args) {
        new test.Test();  // Expected error
    }
}

EDIT:

Just to be clear: it's when I compile Test.java, that I get no warning.

@eRRor 404, I've edited my O.P. to make it clear that I get no warning when I compile Test.java. — user2911290, May 14 '14 at 08:53
@WhoAmI, no I'm using the command prompt shell, with the javac compiler. — user2911290, May 14 '14 at 08:58
The compiler settings can be modified to mark such cases as "warnings" , "errors" or "correct". In eclipse, you could go to properties --> Java Compiler --> Errors / Warnings to change these settings — TheLostMind, May 14 '14 at 09:00

score 0 · Accepted Answer · answered May 16 '14 at 19:21

0

The user comments made to my original post have helped me solve this problem: I now realise that an IDE will give me the information that I was after, and that just using javac on its own will not. Thanks.

answered May 16 '14 at 19:21

user2911290

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javac gives no warning when a class with default access contains public members

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