Detect end of line in C

Question

This is the code which read a matrix 10x10 from a file "F1.txt"

#include <stdio.h>

int main( int argc, char ** argv ) {

    FILE * fr;
    fr = fopen("F1.txt","r");

    int i, j;
    int matrix[10][10] = {0.0}; 

    for(i = 0; i < 10; i++)
    {
        for(j = 0; j < 10; j++)
        {
            fscanf(fr, "%d",&matrix[i][j]);
            printf("%d\n", matrix[i][j]);
        }
    }

    getchar();
    return 0;
}

"F1.txt" looks like this:

12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 4 34 56 43 32 124 52 212 3
32 343 34 544 43 32 7 52 456 98

It works without problems but the output is:

12
343
34
544
43
32
124
52
212
3
12
343
34
544
43
32
124
52
212
..........
etc....

I have to detect the end of line to make my input the same like in F1.txt

12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 343 34 544 43 32 124 52 212 3
12 4 34 56 43 32 124 52 212 3
32 343 34 544 43 32 7 52 456 98

.

`int matrix[10][10] = {0.0};` You mean `int matrix[10][10] = {0};`, right? — herohuyongtao, May 09 '14 at 09:56
this question doesn't show any research and effort. Just replacing `\n` character to ` ` will done the maximum job. — gangadhars, May 09 '14 at 10:12

score 4 · Accepted Answer · answered May 09 '14 at 10:00

4

Rewrite the loops the following way

for(i = 0; i < 10; i++)
{
    for(j = 0; j < 10; j++)
    {
        fscanf(fr, "%d",&matrix[i][j]);
        printf("%3d ", matrix[i][j]);
    }
    printf( "\n" );
}

answered May 09 '14 at 10:00

Vlad from Moscow

301,070
26
186
335

score 2 · Answer 2 · answered May 09 '14 at 10:01

You are reading the data correctly, but you are not printing it right. Your program inserts '\n' after each character, that's why you see so many lines.

Change your program like this to see the output that you expect:

for(i = 0; i < 10; i++)
{
    for(j = 0; j < 10; j++)
    {
        fscanf(fr, "%d",&matrix[i][j]);
        printf("%d ", matrix[i][j]); // <<== Replace \n with a single space
    }
    printf("\n"); // <<== Add this line
}

score 2 · Answer 3 · edited May 09 '14 at 10:08

2

Or if you just want your input formatted, you can write your end of line in the outer loop on i.

for(i = 0; i < 10; i++)
{
    for(j = 0; j < 10; j++)
    {
        fscanf(fr, "%d",&matrix[i][j]);
        printf("%d\t", matrix[i][j]);
    }
    printf("\n");
}

edited May 09 '14 at 10:08

0xF1

6,046
2
27
50

answered May 09 '14 at 10:01

Kmikzy

31
5

score 0 · Answer 4 · answered May 09 '14 at 09:58

For your knowledge, EOL is usually a LF character or combination of CR-LF characters. In C they are represented by \n or \r\n respectively.

A possible solution is that you can use fgets to read a complete line at once (fgets will read one line only by itself). Then read out the integers from that string using sscanf or strtok.

I suggest you to use sscanf if you know number of integers in every line.

Otherwise, if a line can contain any amount of numbers then you can use strtok with " " (space) as the delimitter.

You can read more about these functions here: sscanf , strtok

score 0 · Answer 5 · answered May 09 '14 at 10:01

0

fscanf(fr, "%d",&matrix[i][j]);
printf("%d", matrix[i][j]);
if(j < 10-1)
    printf(" ");
else
    printf("\n");

answered May 09 '14 at 10:01

BLUEPIXY

39,699
7
33
70

Detect end of line in C

5 Answers5