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I'm working in MATLAB and I have the following cell array:

pippo = 

'FSize'           [       10]
'MSize'           [       10]
'rho'             [      997]
'u2'              [  86.2262]
'n'               [      100]
'nimp'            [        2]
'impeller1dir'    [1x66 char]
'impeller2dir'    [1x66 char]
'comparedir'      [1x57 char]

I would like to return the content of the cell, in the second column, which corresponds to a given value for the cell in the first column of the first row. I.e., if the input is 'nimp', I want to return 2. Is there a simple way to do this which doesn't involve looping, or is looping the only way?

DeltaIV
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1 Answers1

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Two methods to do this are containers.Map and logical indexing

Logical indexing

firstly we will find the occurance of the input in the first column with strcmp using ind=strcmp(pippo(:,1),'nimp') and then get the contents of the cell in the second column where this is true pippo{ind,2}

which can be combined into one line with 

out = pippo{strcmp(pippo(:,1),'nimp'),2}

containers.Map

using containers.Map you can map the keys in the first column to the values in the second column this information is stored as a container, below this is the pippo2 variable

pippo2=containers.Map(pippo(:,1),pippo(:,2))

and then you can call the container with an argument of the key and get the value as output

out=pippo2('nimp')

out =

     2
RTL
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  • Amazing! I tried logical indexing, but this way: `ind=pippo(:,1)=='nimp'` and this way: `ind=pippo(:,1)=='nimp'`. However, neither worked. I didn't think about strcmp! The containers.Map trick is neat, too. Thanks a lot! – DeltaIV May 07 '14 at 10:05