Selenium send_keys doesn't work if input type="number"

Question

I'm writing tests using selenium. In those tests I need to enter a number into a field in a form.

Here is the html:

<!DOCTYPE html>
<html>
<head>
</head>
<body>

<form>
    <input type="number" id="field_id">
</form>


</body>
</html>

And the code:

browser = webdriver.Firefox()
browser.get('file:///home/my_username/test.html')
field = browser.find_element_by_id('field_id')
field.send_keys('12')  # NOTHING HAPPEN!

BTW, if I change the type of the field to "text" for example there is no problem at all. In addition, field.send_keys(Keys.UP) work great (but doesn't work when I'm using bootstrap) and field.clear() work all the time, as well as field.click().

Selenium version: 2.41.0 Firefox version: 29.0

What if you call `send_keys` in a loop: `for x in '12': field.send_keys(x)`? — alecxe, May 01 '14 at 17:25
What happens if you click the field first? Also, can you manually enter values in the field? — Robbie Wareham, May 01 '14 at 20:55
@RobbieWareham Clicking the field manually doesn't help. `field.click()` **does** focus on the input field. `field.send_keys` also focus on the field but nothing more. — Nagasaki45, May 01 '14 at 20:59

score 6 · Accepted Answer · edited May 23 '17 at 12:30

6

Because you are using Firefox 29. Please downgrade to Firefox 28, which is the one Selenium 2.41.0 supports to, see CHANGES file. Otherwise you need to wait for new Selenium updates.

Here is what I have tested working with Firefox 28:

from selenium import webdriver

DEMO_PAGE = '''
    data:text/html,
    <form><input type="number" id="field_id"></form>
'''

browser = webdriver.Firefox()
browser.get(DEMO_PAGE)

input_number = browser.find_element_by_id('field_id')
input_number.send_keys('12')

input_number_value = input_number.get_attribute('value')
print "input_number_value = " + input_number_value

See also: Selenium can't find fields with type number

edited May 23 '17 at 12:30

Community

1
1

answered May 01 '14 at 21:12

Yi Zeng

32,020
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With multiple versions of firefox installed, how would I tell selenium to use a specific one? – Eldamir Jun 01 '14 at 10:17
Is there a Selenium bug report for this? Can you provide a link? – cjerdonek Aug 30 '14 at 17:37
Also, it still doesn't seem to work even with Firefox 31 (tested on Sauce Labs with Linux configured). – cjerdonek Aug 30 '14 at 17:43
I created an issue for this in the Selenium tracker here: https://code.google.com/p/selenium/issues/detail?id=7809 – cjerdonek Aug 30 '14 at 18:01

score 5 · Answer 2 · edited May 23 '17 at 11:53

I'm on Fedora (which doesn't provide old versions of packages like Firefox) so "downgrade Firefox" is a bit of a non-answer.

Luckily, an answer to a very similar question hints at a better solution -- setting the "dom.forms.number" Firefox preference to disable special treatment of input type="number". In Python:

profile = webdriver.FirefoxProfile()                                    
profile.set_preference("dom.forms.number", False)                       
browsers = webdriver.Firefox(profile)

Working with Firefox 29 and Selenium 2.41.0

score 2 · Answer 3 · answered Jul 22 '14 at 08:57

I ran into this problem this morning. After upgrading Selenium, it now works properly.

So if you are reading this, run

pip install -U selenium

and try again. I went from Selenium version 2.41.0 to 2.42.1 and it now works properly with Firefox 30.0.

score 0 · Answer 4 · edited Mar 12 '15 at 03:44

0

You can probably use Javascript to tackle this issue. The following code is in Java, but it can probably be done similarly in Python:

((IJavaScriptExecutor)webdriver)
     .ExecuteScript("document.getElementById('field_id').value='12';");

I had the same issue and using Javascript solved it.

edited Mar 12 '15 at 03:44

sth

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answered Mar 12 '15 at 00:51

saurav kakshapati

1

corting · Answer 5 · 2016-05-18T09:14:05.490

In my case selenium Send_keys work fine in this way.

from selenium import webdriver
from selenium.webdriver.common.keys import Keys

browser = webdriver.Firefox()

browser.get('http://www.yahoo.com')
assert 'Yahoo' in browser.title

elem = browser.find_element_by_name('p')  # Find the search box
elem.send_keys('seleniumhq' + Keys.RETURN)

browser.quit()enter code here`

it is the web https://pypi.python.org/pypi/selenium

score 0 · Answer 6 · answered May 24 '16 at 16:39

0

I resolved this issue in this way:

locator =  <element xpath>
field = browser.find_element_by_xpath(to_unicode(**locator**,"utf-8")) 
if(field != None):
     field.send_keys(Keys.CONTROL + 'a')
     field.send_keys(value)

answered May 24 '16 at 16:39

Feten Besbes

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Selenium send_keys doesn't work if input type="number"

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