JSON - Unable to serialize JSONObject within Object using Jackson

Question

I have the following class:

class A{    
    String abc;
    String def;
    // appropriate getters and setters with JsonProperty Annotation 
}

and I call Jacksons objectMapper.writeValueAsString(A) which works fine.

Now I need to add another instance member:

class A{    
    String abc;
    String def;
    JSONObject newMember; // No, I cannot Stringify it, it needs to be JSONObject
    // appropriate getters and setters with JsonProperty Annotation 
}

but when I serialize, I am getting exception:

org.codehaus.jackson.map.JsonMappingException: No serializer found for class org.json.JSONObject and no properties discovered to create BeanSerializer

I tried JSONNode but it gave Output as {outerjson:"{innerjson}"} not {outerjson:{innerjson}}.

Is it possible to use Jackson to achieve the above output, i.e. JSONObject within JSONObject?

enter image description here

Can you show the expected output from a given input? – Sotirios Delimanolis Apr 29 '14 at 14:48 — Sotirios Delimanolis, Apr 29 '14 at 14:48
Why not use the ```ObjectNode``` provided by Jackson? – oceansize Apr 29 '14 at 15:04 — oceansize, Apr 29 '14 at 15:04

score 6 · Answer 1 · answered Nov 28 '18 at 14:35

6

What about to use jackson-datatype-json-org

// import com.fasterxml.jackson.datatype.jsonorg.JsonOrgModule;

ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JsonOrgModule());

See https://github.com/FasterXML/jackson-datatype-json-org

answered Nov 28 '18 at 14:35

banterCZ

1,551
1
22
37

Unclear why this has been down-voted, it worked for me and I always prefer to use an existing library than rolling my own solution. – Stuart Leyland-Cole Feb 26 '20 at 11:17
This should be the anwers : the project has move there https://github.com/FasterXML/jackson-datatypes-misc/tree/master/json-org – VinyJones Feb 22 '21 at 15:52

score 3 · Answer 2 · answered May 03 '14 at 20:57

Well, if you cannot replace the JSONObject on a POJO or a Map, then you can write a custom serializer. Here is an example:

public class JacksonJSONObject {

    public static class MyObject {
        public final String string;
        public final JSONObject object;

        @JsonCreator
        public MyObject(@JsonProperty("string") String string, @JsonProperty("object") JSONObject object) {
            this.string = string;
            this.object = object;
        }

        @Override
        public String toString() {
            return "MyObject{" +
                    "string='" + string + '\'' +
                    ", object=" + object +
                    '}';
        }
    }

    public static void main(String[] args) throws IOException {
        ObjectMapper mapper = new ObjectMapper();
        SimpleModule module = new SimpleModule("org.json");
        module.addSerializer(JSONObject.class, new JsonSerializer<JSONObject>() {
            @Override
            public void serialize(JSONObject value, JsonGenerator jgen, SerializerProvider provider) throws IOException {
            jgen.writeRawValue(value.toString());
            }
        });
        module.addDeserializer(JSONObject.class, new JsonDeserializer<JSONObject>() {
            @Override
            public JSONObject deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException {
                Map<String, Object> bean = jp.readValueAs(new TypeReference<Map<String, Object>>() {});
                return new JSONObject(bean);
            }
        });
        mapper.registerModule(module);
        JSONObject object = new JSONObject(Collections.singletonMap("key", "value"));
        String json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(new MyObject("string", object));

        System.out.println("JSON: " + json);
        System.out.println("Object: " + mapper.readValue(json, MyObject.class));
    }
}

Output:

JSON: {
  "string" : "string",
  "object" : {"key":"value"}
}
Object: MyObject{string='string', object={"key":"value"}}

score 3 · Answer 3 · answered Feb 17 '19 at 01:49

Use @JsonSerialize with the attribute and implement a custom serializer.

@JsonSerialize(using = JsonObjectSerializer.class)
private JSONObject jsonObject;

public static class JsonObjectSerializer extends JsonSerializer<JSONObject> {

    @Override
    public void serialize(JSONObject jsonObject, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException {
        jsonGenerator.writeRawValue(jsonObject.toString());
    }
}

score 0 · Answer 4 · answered Nov 03 '17 at 21:09

0

Use JsonNode instead of JSONObject.

JsonNode jsonNode = JsonLoader.fromString(YOUR_STRING);

answered Nov 03 '17 at 21:09

Brijesh Patel

417
5
11

JSON - Unable to serialize JSONObject within Object using Jackson

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