Call to undefined function with PHP

Question

I have this class:

class testclass{
    function func1(){
        return "hello";
    }
    function func2(){
        echo func1();
    }
}

When I am running

$test = new testclass();
$test->func2();

I get an error: Fatal error: Call to undefined function func1() with the line index of echo func1();

My question now is, how do I make the func2 recognize func1

Is this a problem with the scopes?

`func1()` refers to the *global* function `func1()`. Not the `func1()` of the current class. To call the `func1()` in the current class you'd use `$this->func1()` (or `self::func1()` if it's a static method) — h2ooooooo, Apr 29 '14 at 10:46

score 5 · Accepted Answer · edited May 23 '17 at 12:28

5

function func2(){
        echo func1();
    }

should be

function func2(){
        echo $this->func1();
    }

edited May 23 '17 at 12:28

Community

answered Apr 29 '14 at 10:45

Abhik Chakraborty

and where is the difference to `echo testclass::func1()` ? – Friedrich Apr 29 '14 at 10:46
The `::` operator indicates that `func1()` is a static method of `testclass`, which isn't the case. – BenM Apr 29 '14 at 10:48
You can check more about this here http://stackoverflow.com/questions/3481085/self-vs-classname-inside-static-classname-metods-in-php – Abhik Chakraborty Apr 29 '14 at 10:50

score 1 · Answer 2 · answered Apr 29 '14 at 10:45

1

You're using OO techniques, so you'll have to use the $this keyword to access the func1() function:

class testclass
{
    function func1()
    {
        return "hello";
    }
    function func2()
    {
        echo $this->func1();
    }
}

answered Apr 29 '14 at 10:45

BenM

score 0 · Answer 3 · answered Apr 29 '14 at 10:48

You have error in your code, you cannot invoke the function like this, the proper way is by using $this (which refers to the class itself):

class testclass
{
    function func1()
    {
        return "hello";
    }
    function func2()
    {
        echo $this->func1();
    }
}

3 Answers3