java, android - breakout game - ball paddle bouncing

Asked Apr 28 '14 at 09:46

Active Apr 28 '14 at 09:46

Viewed 353 times

I made a simple breakout game for Android, and I have some problems when the ball reaches the bar (paddle). ball, bar are bitmaps. x,y are the positions of the ball, bx and by are the positions of the bar (paddle). speedX and speedY are the speed of the ball. this isn't a very nice solution. Where can I change the code?

if (y + ball.getHeight() >= c.getHeight()
                    - (10 + bar.getHeight())
                    && (x + ball.getWidth() / 2) >= bx - bar.getWidth() / 2
                    && (x + ball.getWidth() / 2) <= bx + bar.getWidth() / 2) {
                mp.start();

                xdirection = (((x + ball.getWidth()) / 2) - ((bx + bar
                        .getWidth())) / 2) / (bar.getWidth() / 2);

                speedY = -speedY;
                speedX = (speedX) * Math.abs(xdirection);

asked Apr 28 '14 at 09:46

padar_cs

Do you have any issue? – Phantômaxx Apr 28 '14 at 09:52
yes, but the ball moves incorrect. if the ball reaches the left side of the paddle, the ball moves with right direction and not with left direction – padar_cs Apr 28 '14 at 10:18
so, invert the X (multiply by -1)... – Phantômaxx Apr 28 '14 at 10:20
little bit better, but after 30-40 play speedX will be 0 or really near to zero. – padar_cs Apr 28 '14 at 12:15
So you have to rethink your coordinate system. If minX = 0, then maxX must be as wide as the gamefield. If minX = -1 * (gameField.width / 2), then maxX has to be gameField.width / 2. – Phantômaxx Apr 28 '14 at 12:20

java, android - breakout game - ball paddle bouncing

0 Answers0