check if string exceeds limited characters then show '...'

Question

I want list some items in the list but upto some few characters, if the characters limit reaches then just show ....

I have this echo(substr($sentence,0,29)); but how put it condition ?

score 10 · Accepted Answer · edited Jul 24 '18 at 15:02

10

Use mb_strlen() and an if

$allowedlimit = 29;
if(mb_strlen($sentence)>$allowedlimit)
{
    echo mb_substr($sentence,0,$allowedlimit)."....";
}

or in a simpler way... (using ternary operator)

$allowedlimit = 29;
echo (mb_strlen($sentence)>$allowedlimit) ? mb_substr($sentence,0,$allowedlimit)."...." : $sentence;

in a function:

function app_shortString($string, $limit = 32) {
     return (mb_strlen($string)>$limit) ? mb_substr($string,0,$limit)." ..." : $string;
}

edited Jul 24 '18 at 15:02

Andrei Goea

5
4

answered Apr 25 '14 at 11:35

Shankar Narayana Damodaran

68,075
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Why *mb_* instead of just `strlen`? (You can use [mb overloading](http://www.php.net/manual/en/mbstring.overload.php), of course.) – kojiro Apr 25 '14 at 11:42
@ShankarDamodaran So the choice is between `mb_string`, which is an external dependency, or `substr`, which doesn't support multibyte characters, but is built in every default install. – kojiro Apr 25 '14 at 11:48
1

@ShankarDamodaran Actually, the manual only says it's unstable in per-directory context. Presumably that means `` context in apache configs. It should be as stable as anything else in regular php.ini. – kojiro Apr 25 '14 at 11:50

Realitätsverlust · Answer 2 · 2014-04-25T11:46:10.523

3

This should do it:

if(strlen($sentence) >= 30) {
    echo substr($sentence,0,29)."...";
} else {
    echo $sentence;
}

More infos about strlen(): http://www.php.net/manual/de/function.strlen.php

Edit/ Crap, wrong function in mind, sry. ._.

edited Apr 25 '14 at 11:46

answered Apr 25 '14 at 11:34

Realitätsverlust

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1

I tested this with text longer than 29 characters and didn't work. – Funk Forty Niner Apr 25 '14 at 11:44
1

Scratch that last comment. You forgot the `$` in your `(sentence)` in your original code. – Funk Forty Niner Apr 25 '14 at 11:46
Well i had a typo in the if, but its fixed now. It works fine on my machine here. Wheres the error? – Realitätsverlust Apr 25 '14 at 11:47
1

@Fred-ii- xD Yes, i thought that this was the error, fixed it already. :D – Realitätsverlust Apr 25 '14 at 11:48

score 1 · Answer 3 · answered Apr 25 '14 at 11:44

$text = 'this is a long string that is over 28 characters long';

strlen($text) > 28 ? substr($text, 0, 28) .'...' : $text;

gives: this is a long string that i...


$text = 'this is a short string!';

echo strlen($text) > 28 ? substr($text, 0, 28) .'...' : $text;

gives: this is a short string!

check if string exceeds limited characters then show '...'

3 Answers3