Parsing Domainname From URL In PHP

Question

How I can parse a domain from URL in PHP? It seems that I need a country domain database.

Examples:

http://mail.google.com/hfjdhfjd/jhfjd.html -> google.com
http://www.google.bg/jhdjhf/djfhj.html -> google.bg
http://www.google.co.uk/djhdjhf.php -> google.co.uk
http://www.tsk.tr/jhjgc.aspx -> tsk.tr
http://subsub.sub.nic.tr/ -> nic.tr
http://subsub.sub.google.com.tr -> google.com.tr
http://subsub.sub.itoy.info.tr -> itoy.info.tr

Can it be done with whois request?

Edit: There are few domain names with .tr (www.nic.tr, www.tsk.tr) the others are as you know: www.something.com.tr, www.something.org.tr

Also there is no www.something.com.bg, www.something.org.bg. They are www.something.bg like the Germans' .de

But there are www.something.a.bg, www.something.b.bg thus a.bg, b.bg, c.bg and so on. (a.bg is like co.uk)

There on the net must be list of these top domain names.

Check how is coloured the url http://www.agrotehnika97.a.bg/ in Internet Explorer. Check also

www.google.co.uk<br>
www.google.com.tr<br>
www.nic.tr<br>
www.tsk.tr

Note, that *co.uk*, *com.tr* and *info.tr* itself are completely valid domains/host names, and all those are *not* top level domains. As such `google` in `google.co.uk` is *just* a subdomain of `co.uk`. Given that you can freely combine nearly everything, you probably won't be able to make a complete table for that.. — poke, Feb 24 '10 at 17:19
@poke, I saw the list in a web site. Firefox was/is using the list of that website. But I do not remember it. — ilhan, Feb 24 '10 at 17:27

Franz · Accepted Answer · 2010-02-24T17:15:42.200

3

The domain is stored in $_SERVER['HTTP_HOST'].

EDIT: I believe this returns the whole domain. To just get the top-level domain, you could do this:

// Add all your wanted subdomains that act as top-level domains, here (e.g. 'co.cc' or 'co.uk')
// As array key, use the last part ('cc' and 'uk' in the above examples) and the first part as sub-array elements for that key
$allowed_subdomains = array(
    'cc'    => array(
        'co'
    ),
    'uk'    => array(
        'co'
    )
);

$domain = $_SERVER['HTTP_HOST'];
$parts = explode('.', $domain);
$top_level = array_pop($parts);

// Take care of allowed subdomains
if (isset($allowed_subdomains[$top_level]))
{
    if (in_array(end($parts), $allowed_subdomains[$top_level]))
        $top_level = array_pop($parts).'.'.$top_level;
}

$top_level = array_pop($parts).'.'.$top_level;

edited Feb 24 '10 at 17:15

answered Feb 24 '10 at 16:57

Franz

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This isn't quite what ilhan is after. – a'r Feb 24 '10 at 17:00
It still doesn't work even after the edit ;-). It does not deal with the google.co.uk case, as this would return 'co.uk'. – a'r Feb 24 '10 at 17:06
Well, how should a computer know whether a domain is meant to be a subdomain or not then without manually adding all examples like `co.uk`, `co.cc` and so on? I'll try to edit mine, though. – Franz Feb 24 '10 at 17:10
Better now? I added an option to manually specify these exceptions. – Franz Feb 24 '10 at 17:16
I guess you can use the list at http://publicsuffix.org/list and convert it to this format (I'd suggest using a script) ;) – Franz Feb 24 '10 at 17:18

score 1 · Answer 2 · answered Feb 24 '10 at 17:00

1

You can use parse_url() to split it up and get what you want. Here's an example...

    $url = 'http://www.google.com/search?hl=en&source=hp&q=google&btnG=Google+Search&meta=lr%3D&aq=&oq=dasd';
    print_r(parse_url($url));

Will echo...

Array
(
    [scheme] => http
    [host] => www.google.com
    [path] => /search
    [query] => hl=en&source=hp&q=google&btnG=Google+Search&meta=lr%3D&aq=&oq=dasd
)

answered Feb 24 '10 at 17:00

casraf

21,085
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1

I did the same mistake in the beginning. He only wants `google.com`, though. – Franz Feb 24 '10 at 17:02
1

I see. Fair enough -- he can `preg_match()` to get the rest. Assuming `$url_split` is the parsed URL -- this can be done with... `preg_match('/www\.?([\w\-\.]+)([a-z\.]+)/i', $url_split['host'], $matches)` -- he can then use `$matches[1].$matches[2]` to fetch the host without the first domain. Problem with this though, is you can never predict how far the subdomain goes -- it could be `sub1.sub2.domain.co.uk` -- this would fetch `sub2.domain.co.uk`, not `domain.co.uk` – casraf Feb 24 '10 at 17:11

score 1 · Answer 3 · answered Feb 24 '10 at 17:16

I reckon you'll need a list of all suffixes used after a domain name. http://publicsuffix.org/list/ provides an up-to-date (or so they claim) of all suffixes in use currently. The list is actually here Now the idea would be for you to parse up that list into a structure, with different levels split by the dot, starting by the end levels:

so for instance for the domains: com.la com.tr com.lc

you'd end up with:

[la]=>[com]
[lc]=>[com]

etc...

Then you'd get the host from base_url (by using parse_url), and you'd explode it by dots. and you start matching up the values against your structure, starting with the last one:

so for google.com.tr you'd start by matching tr, then com, then you won't find a match once you get to google, which is what you want...

score 1 · Answer 4 · answered Jun 20 '16 at 10:41

Regex and parse_url() aren't solution for you.

You need package that uses Public Suffix List, only in this way you can correctly extract domains with two-, third-level TLDs (co.uk, a.bg, b.bg, etc.). I recomend use TLD Extract.

Here example of code:

$extract = new LayerShifter\TLDExtract\Extract();

$result = $extract->parse('http://subsub.sub.google.com.tr');
$result->getRegistrableDomain(); // will return (string) 'google.com.tr'

Parsing Domainname From URL In PHP

4 Answers4

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