Separate file name from path

Question

I have a file whose path is like this : D:\Documents and Settings\user\Desktop\Folder\File1.txt. Here File1.txt is file name. Now I want to separate this file name from the file path. If I have,

path = C:\Documents and Settings\user\Desktop\Folder\File1.txt

then I want to store this name of the file in to filename. so output will look like this : filename=File1.txt I am not getting any idea about this. I am new in python..can anybody help me please in python...???

I am working on client-server networking in python. I have to send this file name to server. for this I've to separate this file name.so I've wrote complete code for client and server in python. — Ruchir, Apr 23 '14 at 06:02
possible duplicate of [Python, extract file name from path, no matter what the os/path format](http://stackoverflow.com/questions/8384737/python-extract-file-name-from-path-no-matter-what-the-os-path-format) — Vincent Savard, Apr 23 '14 at 06:04

score 8 · Answer 1 · edited Apr 23 '14 at 06:50

8

use os module

import os 
fileName = os.path.basename(path)

edited Apr 23 '14 at 06:50

Nishant Nawarkhede

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answered Apr 23 '14 at 06:02

Abhishek Bansal

5,197
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score 1 · Answer 2 · answered Apr 23 '14 at 06:22

1

If you have already have pathname, just split it and extract the filename from it

path = "C:\\Documents and Settings\\user\\Desktop\\Folder\\File1.txt"
temp=path.split('\\')
filename=temp[-1]
print filename

answered Apr 23 '14 at 06:22

Jry9972

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Nishant Nawarkhede · Answer 3 · 2014-04-23T06:46:04.247

0

If you want file name without knowing what os is ,

try this ,

>>> import ntpath
>>> ntpath.basename("C:\Documents and Settings\user\Desktop\Folder\File1.txt")
'File1.txt'
>>> ntpath.basename("/etc/apache-perl/httpd.conf")
'httpd.conf'

edited Apr 23 '14 at 06:46

answered Apr 23 '14 at 06:28

Nishant Nawarkhede

8,234
12
59
81

Separate file name from path

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