Implementing a Linear Search

Question

The question: Read up to 6 pairs of names and ages into TWO separate arrays, and use a linear search to locate a target name and to print that person’s age. The two arrays are called names and ages:

I am getting lots of errors .. I am not sure about passing the arrays into functions..

  #include <stdio.h>
#define ASIZE 20
#define RECSIZE 6

struct record {
    char name[ASIZE];
    int age[ASIZE];
};
struct record na[RECSIZE];

int linearSearch(struct record *a, char *find)
{
int x;
for(x=0; x<RECSIZE; x++)
{
//  if(na[x].name==find[x])
if(a->name[x]==find[x])
    {
        return x;
    }
}
return -1;
 }

int main()
{
    int i;

    for (i=0; i<RECSIZE; i++)
{
printf("Enter name: ");
scanf("%s",na[i].name);
printf("Enter age: ");
scanf("%i",&na[i].age);
}   

printf("Enter the Search name: ");
char temp[ASIZE];
scanf("%s",temp[ASIZE]);


int result;
result=linearSearch(&na, &temp[]);
printf("%i", result);
    return 0;
    }

Please help.

The error is in: result=linearSearch(&na, &temp[]);

So what would you like us to do? You don't show any of the errors. From looking at your code, I would suggest to get a C book or find tutorials on the net, and read it. — OldProgrammer, Apr 21 '14 at 16:15
result=linearSearch(&na[].name, &na[].age, &temp[]); gives an error saying : Expected expression before ] token — user3541302, Apr 21 '14 at 16:29
1) `if(na[x].name==find[x])` --> strcmp() 2) `linearSearch()` call messed up. — chux - Reinstate Monica, Apr 21 '14 at 16:30

score 0 · Answer 1 · answered Apr 21 '14 at 16:53

0

On my system, the compiler gave me these errors for your exact code. Just look at the line numbers (should be exactly like yours) and address each error by looking at the error description. Once you address these, you will be further down the path of understanding your execution flow:

enter image description here

answered Apr 21 '14 at 16:53

ryyker

22,849
3
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i modified my code.. just check the question again.. I have specified the error i get now... Thank you! – user3541302 Apr 21 '14 at 16:53
Yes, I can see that by looking at the very first line of my compile messages. It is telling you that there is a problem with the operands. In this case you should use `strcmp()` to compare strings, not `==`. i.e. `if(strcmp(a, b) == 0){...}` (substitutions for brevity) – ryyker Apr 21 '14 at 16:57
Also, `char temp[ASIZE];` is a string, not an array of strings. so the strcmp line should look like: `if(strcmp(na[x].name,find))` and not: `if(strcmp(na[x].name,find[x]))` – ryyker Apr 21 '14 at 17:08

BLUEPIXY · Accepted Answer · 2014-04-21T23:13:04.917

#include <stdio.h>
#include <string.h>

#define ASIZE 20
#define RECSIZE 6

struct record {
    char name[ASIZE];
    int age;
};

struct record na[RECSIZE];

int linearSearch(struct record *a, char *find){
    int x;
    for(x=0; x<RECSIZE; x++){
        if(strcmp(a[x].name, find)==0)
            return x;
    }
    return -1;
}

int main(){
    int i;

    for (i=0; i<RECSIZE; i++){
        printf("Enter name: ");
        scanf("%s", na[i].name);//No protection when entered past the buffer
        printf("Enter age: ");
        scanf("%i", &na[i].age);
    }

    printf("Enter the Search name: ");
    char temp[ASIZE];
    scanf("%s", temp);

    int result;
    result=linearSearch(na, temp);
    printf("%i", result);
    return 0;
}

Implementing a Linear Search

2 Answers2