How to prove that any minimum vertex cover of a clique of size n must have exactly n-1 vertices? THx
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1This question appears to be off-topic because it is graph theory rather than a concrete programming or implementation question – talonmies Apr 18 '14 at 15:22
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2This question appears to be off-topic because it is should be asked on http://cs.stackexchange.com/ – Basile Starynkevitch Apr 18 '14 at 15:22
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1This question appears to be off-topic because it shows no effort whatsoever, and reeks of homework. – LittleBobbyTables - Au Revoir Apr 18 '14 at 15:26
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If there's two vertices from the clique not in a set, then the edge between them isn't covered, so any cover must have at least n-1 vertices. Any subset of n-1 vertices is a cover, trivially.

Paul Hankin
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