function that receives a letter then returns the next and previous letters c++

Question

Write a function that receives a letter then returns the next and previous letters. and this is my Solution

#include <iostream>
using namespace std;
void letter(char &x);
int main(){
    char a;
    cout<<"Enter your letter\n:";
    cin>>a;
    cout<<letter(a)<<endl;
    system("pause");
    return 0;}
void letter(char &x){
    cout<<x+1<<"  "<<x-1<<endl;
}

while trying to match the argument list '(std::ostream, void)' what is that mean ?

i solve my problem but the output was numbers how i can Conversion to letter ? — user3526978, Apr 12 '14 at 14:56

score 0 · Answer 1 · answered Apr 12 '14 at 14:49

cout<<letter(a)<<endl;

that have no sense, it's the same that

cout<< void << endl;

becouse your "letter(a)" function return nothing. maybe what you want to change it for:

#include <iostream>
using namespace std;
void letter(char &x);
int main(){
    char a;
    cout<<"Enter your letter\n:";
    cin>>a;
    letter(a);
    system("pause");
    return 0;
}
void letter(char &x){
    cout<<x+1<<"  "<<x-1<<endl;
}

function that receives a letter then returns the next and previous letters c++

1 Answers1