How do I access the first item(or xth item) in a PyQuery query?

Question

I have a query for a one of my tests that returns 2 results. Specifically the 3rd level of an outline found using

query = html("ul ol ul")

How do I select the first or second unordered list?

query[0]

decays to a HTMLElement

list(query.items())[0]

or

query.items().next() #(in case of the first element)

is there any better way that I can't see?

note:

query = html("ul ol ul :first")

gets the first element of each list not the first list.

score 6 · Accepted Answer · answered Apr 14 '14 at 23:04

6

From the PyQuery documentation on traversing, you should be able to select the first unordered list by using:

query('ul').eq(0)

Thus the second unordered list can be obtained by using:

query('ul').eq(1)

answered Apr 14 '14 at 23:04

Talvalin

1

Why did they pick eq? such a bad name, makes me think of ==/__eq__ – Roman A. Taycher Apr 15 '14 at 08:43
1

Agreed. Completely counter-intuitive. – Talvalin Apr 15 '14 at 08:53

score 2 · Answer 2 · answered Apr 14 '14 at 23:08

2

In jQuery one would use

html("ul ol ul").first()

.first() - Reduce the set of matched elements to the first in the set.

or

html("ul ol ul").eq(0)

.eq() - Reduce the set of matched elements to the one at the specified index.

answered Apr 14 '14 at 23:08

CodeManX

1

True, but PyQuery doesn't support the first wayt unfortunately. – Pithikos Jul 21 '17 at 07:24

2 Answers2