URL Format Query String with /

Question

Is there anyone her who knows how to use slashes as querystring. What I want to do is using the url:

http://sample.com/urltest/?id=23423ea342

to appear as

http://sample.com/urltest/23423ea342

and handel it onto the Servlets or Struts Action Class

that's called URL rewriting, but your question is way too broad for SO. So the best thing to do would be googling those terms and learn a bit more from there. — Laurent S., Apr 08 '14 at 13:53
Instead you should have correct Servlet of Action class which have method mapped to `http://sample.com/urltest/` and accepts `id` as request parameter — Ajinkya, Apr 08 '14 at 13:54
You could use a regex and replace {'?id='} through '' (an empty string). http://www.vogella.com/tutorials/JavaRegularExpressions/article.html — user2718671, Apr 08 '14 at 14:08
I dont want a ? Into the query string , it should have only slashes. Is there any tutorial where i can get some idea regarding this ? — Atul Darne, Apr 08 '14 at 14:16

score 0 · Answer 1 · edited Apr 08 '14 at 13:59

0

add this to .htaccess file

RewriteEngine On
RewriteRule ^(.*)$ /sample.com/urltest/?id=$1 [L]

edited Apr 08 '14 at 13:59

BackSlash

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answered Apr 08 '14 at 13:58

Omar Sedki

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You should also explain what this does, otherwise the OP learns nothing from this answer. – BackSlash Apr 08 '14 at 13:59
In addition to the comment above, you should also mention that the `RewriteRule` above will rewrite any requests since it is `.*` (`^` and `$` are not necessary in this case). – Rolice Apr 08 '14 at 14:05
I have seen many payment gateways or reportieng tools that use this way of url e.g http://www.gateway.com/userauth/txn678257/reportxml/ – Atul Darne Apr 08 '14 at 14:21

Cirou · Answer 2 · 2014-04-08T14:44:55.250

Well, if i understood what is OP asking for, the simplest way for me to do this is use JAX-RS, aka Java API for RESTful Web Services

Here is the JAX-RS oracle tutorial: http://docs.oracle.com/javaee/6/tutorial/doc/giepu.html

And here is an example service class for your example URL:

@Path("/")
public class testClass {

    @GET
    @Path("/{id}/")
    @Produces(MediaType.APPLICATION_JSON)
    public Response testMethod(@PathParam(value = "id") String id) {

        return Response.ok().entity("HELLO! You sent me this id: " + id).build();

    }

}

Assuming that /urltest is the path configured for your base url, this service will be invoked with the following URL: http://sample.com/urltest/23423ea342

and the "23423ea342" will be your {id} parameter for your service

URL Format Query String with /

2 Answers2