Checking a String in an array for brace (java)

Question

so i'm currently trying to check whether or not there's a brace in a String in an array, but I can't figure out how its done.

    public void braceChecker()
    {
         String[] code = new String[]{"{} [] () {"};         
         System.out.println(code[0].charAt(0) == "{");
    }

Obviously, it errors on the last print statement, but I can't find a way to check that character without java yelling at me. If I take "{" out of the string, it interprets it as an actual brace. How do I go about this?

Why are you using a 1-element `String[]` and not a `String`? — Matt Ball, Apr 05 '14 at 21:23

score 3 · Answer 1 · answered Apr 05 '14 at 21:22

3

Change the "{" to '{' (your want a character literal, not a string literal).

See Character and String Literals in the tutorial.

answered Apr 05 '14 at 21:22

NPE

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score 1 · Answer 2 · answered Apr 05 '14 at 21:23

1

Use

System.out.println(code[0].charAt(0) == '{');

instead, "" is a String

answered Apr 05 '14 at 21:23

betteroutthanin

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score 0 · Answer 3 · answered Apr 05 '14 at 21:23

0

Change it to single quotes to compare as a character.

answered Apr 05 '14 at 21:23

shree.pat18

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score 0 · Answer 4 · answered Apr 05 '14 at 21:24

A char is compared to by using single quotes ' not double quotes " which are used for Strings.

public void braceChecker()
{
     String[] code = new String[]{"{} [] () {"};
     System.out.println(code[0].trim());
     System.out.println(code[0].charAt(0) == '{');
}

Checking a String in an array for brace (java)

4 Answers4