ExecuteScalar Error when Creating Custom ID

Question

im currently facing problem with executeScalar when i create custom ID. the error is

InvalidOperationException was unhandled by user code.

Message=Connection must be valid and open.

Below is my code :

Dim str As String = "select isnull(max(idcr_record),0)+1 from cr_record where Emplid = '" & Session("Emplid") & "'"
Dim com As New MySqlCommand()
'this line was the error
'
Dim count As Integer = Convert.ToInt32(com.ExecuteScalar())

If count = 1 Then
    'insert if no record found
    '
    Dim cc As New MySqlCommand("insert into cr_record values (" & count & "," & Session("Emplid") & ")")
    cc.ExecuteNonQuery()
Else
    'update becoz record already exist
    '
    Dim upd As String = "update cr_record set idcr_record = " & count & " where Emplid = " & Session("Emplid") & " "
    Dim cc As New MySqlCommand(upd)
    cc.ExecuteNonQuery()
End If

Dim length As Integer = 0
Dim val As String = Convert.ToString(count)
length = val.Length
If length = 1 Then
    val = "CR " + "00000" & Convert.ToString(count)
End If
If length = 2 Then
    val = "CR " + "0000" & Convert.ToString(count)
End If
If length = 3 Then
    val = "CR " + "000" & Convert.ToString(count)
End If
If length = 4 Then
    val = "CR " + "00" & Convert.ToString(count)
End If
If length = 5 Then
    val = "CR " + "0" & Convert.ToString(count)
End If
cr_id = "" & val

where are you opening your connection? i.e. Dim con as new MySqlConnection(connectionstringvariable) — attila, Apr 02 '14 at 02:11
@attila owh i must also open connection again..because i have already open connection when it start running..i will try yours suggestion tq — kolapopo, Apr 02 '14 at 02:29
@attila i just make an oppen connection it still facing the same error.. — kolapopo, Apr 02 '14 at 02:39

har07 · Accepted Answer · 2014-04-02T07:12:01.170

At least, you need to pass your SQL command string and SqlConnection object to SqlCommand object before you can execute the command :

Dim str As String = "select isnull(max(idcr_record),0)+1 from cr_record where Emplid = '" & Session("Emplid") & "'"
Dim conn As New MySqlConnection
conn.ConnectionString = "....."

'pass your SQL command string and MySqlConnection object to MySqlCommand
'
Dim com As New MySqlCommand(str, conn)

conn.Open()
Dim count As Integer = Convert.ToInt32(com.ExecuteScalar())

ExecuteScalar Error when Creating Custom ID

1 Answers1