How to call a method in Android from onCreate

Question

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    chustilla();}


public void chustilla (View v){ //Do anything }

When I compile it gives me a problem in the parameter of chustilla(). What can I do to call this method from onCreate?

PD: If I put "this" or "null" inside the brackets it doesn't work aswell

score 2 · Answer 1 · answered Mar 31 '14 at 16:35

chustilla(View) requires a View reference to be passed as a parameter so it won't work if you don't pass a View reference to it. According to what is done inchustilla(View) (best known to you) you can pass it a View from the layout (Also, best known to you).

score 1 · Answer 2 · edited Mar 31 '14 at 16:41

1

Your method public void chustilla (View v) expects to be passed a View object. But in onCreate() You simply call chustilla(). You need pass it a view object.

edited Mar 31 '14 at 16:41

EdmDroid

1,350
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answered Mar 31 '14 at 16:33

mbiokyle

152
9

score 1 · Answer 3 · answered Jun 04 '18 at 06:06

1

    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    chustilla(a);
}


public void chustilla (Int a)
{
    //your code
}

answered Jun 04 '18 at 06:06

Raj Bedi

164
3
14

score 0 · Answer 4 · edited Mar 31 '14 at 17:04

0

Try the following:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    chustilla();
}


public void chustilla ()
{
    //Do anything 
}

edited Mar 31 '14 at 17:04

likeitlikeit

5,563
5
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56

answered Mar 31 '14 at 16:44

Ahmad

73
1
5

1

what if chustilla () has two or three parameters, how to call this on onCreate? – Raj Bedi Jun 04 '18 at 06:03

Ahmad · Answer 5 · 2014-03-31T17:06:28.657

0

or use this for example:

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    String s;
    chustilla(s);
}


public void chustilla (String v)
{ //write code here }

edited Mar 31 '14 at 17:06

answered Mar 31 '14 at 16:49

Ahmad

73
1
5

But what if `//Do anything` in @user3481906's code necessarily requires a `View`? – EdmDroid Mar 31 '14 at 17:02
v is a string no View – Ahmad Mar 31 '14 at 17:07
That's what I am saying @user3481694. What if @user3481906's code necessarily requires a `View` to be passed as a parameter to `chustilla()` – EdmDroid Mar 31 '14 at 17:08

score -1 · Answer 6 · answered May 20 '17 at 21:04

example parameter "new View(this)" :

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    chustilla(new View(this));}


public void chustilla (View v){ //Do anything }

How to call a method in Android from onCreate

6 Answers6