Ruby on Rails String to OpenStruct

Question

I have the following OpenStruct object but if I call .class on it is a string. How do I turn it back into a OpenStruct object?

[
 #<OpenStruct source="hkepc.com", visits="8", visitBounceRate="37.5", avgTimeOnSite="199.375", pageviews="25", pageviewsPerVisit="3.125">, 
 #<OpenStruct source="1st-tag.co.uk", visits="6", visitBounceRate="100.0", avgTimeOnSite="0.0", pageviews="6", pageviewsPerVisit="1.0">, 
 #<OpenStruct source="facebook.com", visits="5", visitBounceRate="80.0", avgTimeOnSite="8.2", pageviews="6", pageviewsPerVisit="1.2">
]

Can you please post a working example to reproduce the problem? — toro2k, Mar 31 '14 at 15:20
@MaxRose-Collins the `Object#class` method always returns a `String` (http://ruby-doc.org/core-2.1.1/Object.html#method-i-class) - am I misunderstanding what you are asking? Also, you've posted an `Array` here as opposed to a single `OpenStruct`, so I assumed you are referring to an element of this array. — Andreas Kavountzis, Mar 31 '14 at 15:21
@SergioTulentsev good catch, read the docs but wrote the wrong thing. Updating comment, thanks! — Andreas Kavountzis, Mar 31 '14 at 16:00

Andreas Kavountzis · Accepted Answer · 2014-03-31T16:54:23.063

1

A little bit hacky, but I think achieves your goal:

require 'ostruct'

string_array = '[
 #<OpenStruct source="hkepc.com", visits="8", visitBounceRate="37.5", avgTimeOnSite="199.375", pageviews="25", pageviewsPerVisit="3.125">, 
 #<OpenStruct source="1st-tag.co.uk", visits="6", visitBounceRate="100.0", avgTimeOnSite="0.0", pageviews="6", pageviewsPerVisit="1.0">, 
 #<OpenStruct source="facebook.com", visits="5", visitBounceRate="80.0", avgTimeOnSite="8.2", pageviews="6", pageviewsPerVisit="1.2">
]'

string_array.gsub(/(\n|#<OpenStruct|\[|\]|\s+)/, '').split('>,').map do |attrs|
  struct_attrs = attrs.split(',')
  attrs = struct_attrs.inject({}) do |hash, elem|
    hash[elem.split('=').first] = elem.split('=').last.gsub('"', '')
    hash
  end

  OpenStruct.new(attrs)
end

edited Mar 31 '14 at 16:54

answered Mar 31 '14 at 15:23

Andreas Kavountzis

407
3
9

but at the moment the array is actually a string, if you understand what i mean? – Max Rose-Collins Mar 31 '14 at 15:25
Ah, OK sorry that wasn't clear from the OP. So that mean that these are the `.to_s` versions of these objects most likely... I'm not sure of an approach that would allow you to reconstruct them as `OpenStruct`s without having to parse out the attributes (as mentioned in your comment above). – Andreas Kavountzis Mar 31 '14 at 15:28
That is pretty close to it! but it seems to add extra quotes and slashes? # – Max Rose-Collins Mar 31 '14 at 16:40
@MaxRose-Collins answer updated. Hopefully that works! – Andreas Kavountzis Mar 31 '14 at 16:54
How would I preserve spaces within each `` ? For example `#` United States should have a space between it? – Max Rose-Collins Apr 08 '14 at 10:08
You'll probably need to remove `\s+` from the RegExp, so `string_array.gsub(/(\n|# – Andreas Kavountzis Apr 09 '14 at 20:14
I never did work out this problem. When I remove the \s+ everything is blank – Max Rose-Collins Nov 27 '14 at 13:52

Ruby on Rails String to OpenStruct

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