Converting decimal to binary with user input

Question

I wanna make a c# application that convert a decimal number into binary with the input from the user. I get a red squiggly line on bin, when declaring bin = Convert.ToString(decToBin,2);. I don't understand my problem, so any help would be appreciated.

int decToBin;
Console.WrinteLine("Enter a number that will be converted to binary")
decToBin = Int32.Parse(Console.Readline());

bin = Convert.ToString(decToBin,2);

Console.ReadKey();

And you probably need to print it too... – leppie Mar 27 '14 at 11:55 — leppie, Mar 27 '14 at 11:55

Ehsan · Accepted Answer · 2014-03-27T13:01:47.427

1

i guess you haven't declared bin. it should be

int decToBin;
Console.WriteLine("Enter a number that will be converted to binary");
decToBin = Int32.Parse(Console.ReadLine());
string bin = Convert.ToString(decToBin, 2);
Console.WriteLine(bin);

edited Mar 27 '14 at 13:01

answered Mar 27 '14 at 11:54

Ehsan

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yeah you are right. Thank you for that, but I get another problem. When running this code, the outcome is stil a decimal number instead binary. What do I do wrong? Is my code correct for converting decimal into binary? – TNJ Mar 27 '14 at 12:02
@user3387813 you are getting decimal because you did not convert it into binary! This snippet simply accepts a number in "decToBin", converts it into string using "Convert.ToString()". But you are not converting it anywhere! – Bodhi Mar 27 '14 at 12:04
@Bodhi so ur saying that this line of code shoud be different? string bin = Convert.ToString(decToBin,2); – TNJ Mar 27 '14 at 12:13
@TNJ I am very sorry, i did not see that second parameter in Convert.ToString(). Can you tell me the inputs? – Bodhi Mar 27 '14 at 12:18
@TNJ what do you get in bin. isn't it 101? – Ehsan Mar 27 '14 at 12:20
@Bodhi Basicly I used this code as a converter: string binary = Convert.ToString(31, 2); the outcome will be 11111. I wanna make it dynamic instead hardcoded it. Thats why the first parameter is dynamic, the second is the base 2. Cauze binary is in base 2. – TNJ Mar 27 '14 at 12:33
@Ehsan what do you mean 101? If I run this app and my input is 13(example), the outcome will be 1101. – TNJ Mar 27 '14 at 12:40
@TNJ Yes, this is what i get if i enter 13. 1101. – Ehsan Mar 27 '14 at 12:47
@Ehsan I mean my outcome _italic_ should be 1101. But this code isn't working. I have changed it, but stil it doens't show what I would expected: 'code' string decToBin; 'code' Console.WriteLine("Enter a number to be converted into binary"); 'code' decToBin = Console.ReadLine(); 'code' decToBin = Convert.ToString(decToBin,2) 'code' Console.WrinteLine(decToBin); – TNJ Mar 27 '14 at 13:00
@TNJ you need to write this line at the end. Console.WriteLine(bin); – Ehsan Mar 27 '14 at 13:01
@Ehsan ahh YEss finaly it works. Thank you verry much;-) – TNJ Mar 27 '14 at 13:05
@Ehsan how do i suppose to do that, I'm a noob here. That was my first post of asking a question – TNJ Mar 28 '14 at 09:21
@TNJ see here http://meta.stackexchange.com/questions/23138/how-to-accept-the-answer-on-stack-overflow – Ehsan Mar 28 '14 at 09:43

score 1 · Answer 2 · answered Aug 02 '16 at 15:02

This works well and waits for key after print. you were also missing a comma and some large letters.

   Console.WriteLine("Enter a number that will be converted to binary");
   var decToBin = Int32.Parse(Console.ReadLine());

   Console.WriteLine(Convert.ToString(decToBin,2));

   Console.ReadKey();

score 0 · Answer 3 · answered Mar 27 '14 at 11:59

0

in addition to what Ehsan mentioned,

Console.Readline() should be Console.ReadLine(); L caps

answered Mar 27 '14 at 11:59

Kapil

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helb · Answer 4 · 2014-03-27T12:05:58.790

when declaring bin = Convert.ToString(decToBin,2);.

This is not how you declare variables in C#. The syntax is

<Type> <VariableName> [ = <Value>];

e.g.

string bin = Convert.ToString(decToBin, 2);

or

var bin = Convert.ToString(decToBin, 2);

Also see the C# language specification, §8.5.1:

The local-variable-type of a local-variable-declaration either directly specifies the type of the variables introduced by the declaration, or indicates with the identifier var that the type should be inferred based on an initializer.

Converting decimal to binary with user input

4 Answers4