EOF character is not detected when typing line of text first?

Question

char ch;
while((ch=getc(stdin))!=EOF)
{
    putc(ch,stdout);
}

As we know that EOF character can be inputted by ctrl-z.

I ran the program two times:-

1- When I input ctrl-z, the loop gets terminated, which is acceptable.

2- When I input ctrl-z along with some other text like demo and then press ctrl-z, then the loop does not get terminated.

So my question is that why the loop is getting terminated only by inputing ctrl-z alone?

Which terminal/shell is being used? – user2864740 Mar 26 '14 at 17:31 — user2864740, Mar 26 '14 at 17:31
@user2864740: what it means? – kevin gomes Mar 26 '14 at 17:31 — kevin gomes, Mar 26 '14 at 17:31
i.e. xterm/bash? windows/cmd.exe? – user2864740 Mar 26 '14 at 17:32 — user2864740, Mar 26 '14 at 17:32
I have used the second one – kevin gomes Mar 26 '14 at 17:33 — kevin gomes, Mar 26 '14 at 17:33

score 2 · Answer 1 · answered Mar 26 '14 at 17:21

2

EOF is not a character that you can put into a stream. It's a meta-control character that can be returned by getc, but can not be written. ctrl-z does not technically send EOF, it sends SIGTSTP to the process and getc is programmed to respond to it by returning EOF.

answered Mar 26 '14 at 17:21

Sergey L.

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I agree to it, but why this is not happening in second case – kevin gomes Mar 26 '14 at 17:25
Are you actually typing `demo` and then pressing `ctrl-z` or typing `^z`? The latter will not work on most terminals. – Sergey L. Mar 26 '14 at 17:26
I am typing `demo` and then pressing `ctrl-z` – kevin gomes Mar 26 '14 at 17:27

EOF character is not detected when typing line of text first?

1 Answers1