PHP output string with variable?

Question

I don't understand why it output -2yyy !

How can I output xxx8yyy ?

$ten = 10;
$two = 2;

echo "xxx".$ten - $two."yyy"; //-2yyy

score 2 · Answer 1 · answered Mar 26 '14 at 14:50

2

echo "xxx".($ten - $two)."yyy";

Try this.

answered Mar 26 '14 at 14:50

michal.hubczyk

3

He could probably benefit from an explanation. – superphonic Mar 26 '14 at 14:51
See this answer for very clear explanation http://stackoverflow.com/a/10841238/1743833 – superphonic Mar 26 '14 at 14:58

score 0 · Answer 2 · answered Mar 26 '14 at 14:51

0

Just add brackets:

<?php
$ten = 10;
$two = 2;

echo "xxx".($ten - $two)."yyy"; // xxx8yyy

answered Mar 26 '14 at 14:51

Carsten

2 Answers2