Create xml format c#

Question

I want to make xml format like this in c#

<?xml version='1.0' encoding='us-ascii'?> 
<root>
<key value="22.wav">
<Index>1</Index>
<Index>20</Index>
<Index>21</Index>
</key>
<key value="EFG.wav">
<Index>5</Index>
<Index>22</Index>
</key>
</root>

How do i form like this please help me

Take a look at this. Might help. http://stackoverflow.com/questions/15083727/how-to-create-xml-in-c-sharp — Abhilab Das, Mar 26 '14 at 05:19

score 1 · Answer 1 · answered Mar 26 '14 at 05:06

1

You could use following code:

    XDocument doc = new XDocument(new XDeclaration("1.0", "us-ascii", null),
        new XElement("root",
            new XElement("key", new XAttribute("value", "22.wav"),
                new XElement("Index", 1),
                new XElement("Index", 20),
                new XElement("Index", 21)),
            new XElement("key", new XAttribute("value", "EFG.wav"),
                new XElement("Index", 5),
                new XElement("Index", 22))));
    doc.Save(fileName);

answered Mar 26 '14 at 05:06

Dmitriy Finozhenok

844
7
8

How do i for dynamically – munisamy Mar 26 '14 at 05:16
@munisamy: use the same approach. First, create static part (declaration and root element), then create and add elements dynamically (use XElement.Add method to add child elements) – Dmitriy Finozhenok Mar 26 '14 at 05:30

SpiderCode · Answer 2 · 2014-03-26T05:47:38.283

Best way to achieve this is XMLSerialization. Create a property class as mentioned below and assign values to it :

[Serializable]
[XmlRoot("root")]
public class RootClass
{
    [XmlElement("key")]
    public List<KeyClass> key { get; set; }
}

[Serializable]
[XmlType("key")]
public class KeyClass
{
    [XmlElementAttribute("value")]
    public string KeyValue { get; set; }

    [XmlElement("Index")]
    public List<int> index { get; set; }
}

Now create an XML as mentioned below :

static public void SerializeXML(RootClass details)
{ 
    XmlSerializer serializer = new XmlSerializer(typeof(RootClass)); 
    using (TextWriter writer = new StreamWriter(@"C:\Xml.xml"))
    {
        serializer.Serialize(writer, details); 
    } 
}

How to assign values and generate XML using method SerializeXML:

// Create a New Instance of the Class
var keyDetails = new RootClass();
keyDetails.key = new List<KeyClass>();

// Assign values to the Key property
keyDetails.key.Add(new KeyClass
                        {
                            KeyValue = "22.wav",
                            index = new List<int> { 1, 2, 3}
                        });

keyDetails.key.Add(new KeyClass
{
    KeyValue = "EFG.wav",
    index = new List<int> { 5 , 22 }
});

// Generate XML
SerializeXML(keyDetails);

what do you mean Dynamically ? You can always add KetValue dynamically from your control value. — SpiderCode, Mar 26 '14 at 08:24

score 0 · Answer 3 · edited May 23 '17 at 12:05

Check this article XmlDocument fluent interface

XmlOutput xo = new XmlOutput()
                .XmlDeclaration()
                .Node("root").Within()
                     .Node("key").Attribute("value", "22.wav").Within()
                         .Node("Index").InnerText("1")
                         .Node("Index").InnerText("20")
                         .Node("Index").InnerText("21").EndWithin()
                     .Node("key").Attribute("value", "EFG.wav").Within()
                         .Node("Index").InnerText("2")
                         .Node("Index").InnerText("22");

string s = xo.GetOuterXml();
//or
xo.GetXmlDocument().Save("filename.xml");

For other ways how to build xml in code check the following answers What is the best way to build XML in C# code

Create xml format c#

3 Answers3

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