Why the skipPreamble() return false?

Question

I am using http://commons.apache.org/proper/commons-fileupload/ to parse multipart form and extract an uploaded file. I am following this manual http://www.oreillynet.com/onjava/blog/2006/06/parsing_formdata_multiparts.html and fresh new documentation from inside that package. The request.getContentLength() is saying 700K and that is the code

InputStream input = request.getInputStream();
MultipartStream mStream = new MultipartStream(input, boundArray, 94096 /*random number*/, null);
boolean part = mStream.skipPreamble();

And the part is always false. Could anybody tell me why? Thank you!

score 0 · Answer 1 · answered Mar 21 '14 at 20:53

0

Regarding to code of MultipartStream.java you get MalformedStreamException in discardBodyData or readBoundary.

Looks like discardBodyData only declares that, bun never throws MalformedStreamException.

readBoundary throws MalformedStreamException("Unexpected characters follow a boundary") and MalformedStreamException("Stream ended unexpectedly").

Comment says:

* @throws MalformedStreamException if the stream ends unexpectedly or
*                                  fails to follow required syntax

Hypothesis: 94096 /random number/ is supposed to be buffer size. 94096 is not enough for 700K, so for MultipartStream stream ends unexpectedly.

answered Mar 21 '14 at 20:53

Nikolay

81
3

No, the problem is same for new MultipartStream(input, boundArray, request.getContentLength(), null); – Ekaterina Ivanova iceja.net Mar 22 '14 at 07:39
Could you provide more details about boundArray then. Do you create the same way as article says? What is value you get? – Nikolay Mar 22 '14 at 10:33
Hi! Thank you for your cooperation, but this is not an issue any more. I have found new User Guide here http://commons.apache.org/proper/commons-fileupload/using.html and it works. – Ekaterina Ivanova iceja.net Mar 22 '14 at 13:41

Why the skipPreamble() return false?

1 Answers1