how to convert a Iterator[Long] to Iterator[String] in scala

Question

I have a requirement where I have to convert a Iterator[Long] to Iterator[String] in scala. Please let me know how can I do it

Q&A for producing a true `Iterator[Long]` posted [here](https://stackoverflow.com/questions/72937656/how-to-produce-a-true-iterarorlong-in-scala/72937657#72937657) — Darren Bishop, Jul 11 '22 at 11:15

Jatin · Accepted Answer · 2014-03-10T06:38:51.513

1

Well just like any other collection use map. For example:

scala> val ls = List(1,2,3).toIterator
ls: Iterator[Int] = non-empty iterator

scala> ls.map(_.toString) //it was map(x+""). see comments on why it is bad
res0: Iterator[String] = non-empty iterator

scala> res0.next
res1: String = 1

scala> res0.next
res2: String = 2

scala> res0.next
res3: String = 3

edited Mar 10 '14 at 06:38

answered Mar 10 '14 at 06:01

Jatin

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I think `ls.map(_.toString)` would be a bit more clear. – Chris Martin Mar 10 '14 at 06:15
Ugh, `+""` is awkward, unclear, and relies on [one of the worst parts](https://issues.scala-lang.org/browse/SI-194) of the Scala language. `ls.map(_.toString)` would be at least a little less horrible. – Travis Brown Mar 10 '14 at 06:16
The idiom is `.map("" + _ )` to handle `null`. – som-snytt Mar 10 '14 at 06:24

score 1 · Answer 2 · answered Mar 10 '14 at 06:16

1

scala> List(1,2,3).toIterator.map(_.toString)
res1: Iterator[String] = non-empty iterator

scala> List(1,2,3).toIterator.map(_.toString).mkString(", ")
res2: String = 1, 2, 3

answered Mar 10 '14 at 06:16

Mike Slinn

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how to convert a Iterator[Long] to Iterator[String] in scala

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