pass by value and pass by reference for x and y

Question

Given the pseudo code below, what will be the output of the program, when the two parameters x and y are passed by value, and when they are passed by reference?

int x = 1;
int y = 1; 
int count = 0;
while count < 3{
addnumbers(x, y);
println (x);
count++;
}

addnumbers(int x, int y){
x = x + y;
println (x);
}

I don't think your pseudo code does any passing of any kind. It looks like you are trying to create a method numbers() inside your while loop, but it never gets called. — nick, Mar 03 '14 at 18:02
@RikayanBandyopadhyay It is just psuedocode, but the code is not correct. — Akshay Kalose, Mar 03 '14 at 18:03
It is a pseudocode which I need to solve but I dont know how the mechanism for call by value and call by reference works? — robert, Mar 03 '14 at 18:07

score 0 · Accepted Answer · answered Mar 03 '14 at 18:10

Pass by Value: In pass by value, when you pass a variable into a function, the function will use a copy of the variable, so the original is not affected.

Pass by Reference: In pass by reference, you pass the reference of the variable, so since both int x and int x inside the function reference the same thing, if you change one, the other one changes too.

pass by value and pass by reference for x and y

1 Answers1