I have this on my program and it shows an error saying : Unterminated string.
char Tok[63][63] = {"%%##","\""};
Is there other way to declare the double quotation mark as a string?
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Which platform and compiler are you using? – R Sahu Mar 01 '14 at 06:06
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1That explains a lot, because that passes fine on both clang and clang++ 3.3. If you could have chosen a worse C compiler, I'm pressed to see how. The last Turbo C (2.0) was released literally a quarter-century ago. – WhozCraig Mar 01 '14 at 06:22
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It was a requirement for a project so I need to stick to the compiler. – LorenzKyle Mar 01 '14 at 06:27
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1Replace it with the hex equivalent (byte value) - for example char(0x22) or similar. – Prabindh Mar 01 '14 at 06:32
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1Thanks prabindh that answers my question. – LorenzKyle Mar 01 '14 at 06:40
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Now that I added more elements to the array it doesnt work. It only worls when the byte value is in the end of the array. – LorenzKyle Mar 02 '14 at 02:49
1 Answers
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This is a bug in Turbo C. I have tried:
char Tok[63][63] = { "%%##", "\"" };
int
main (int argc, char **argv)
{
return 0;
};
on gcc, in normal mode, C89 mode, and C99 mode with -Wall and it compiles without errors (*). I have also manually reviewed the string and there is no way it is unterminated.
I suggest you use octal within your string literal, i.e.
char Tok[63][63] = { "%%##", "\042" };
and see if Turbo C likes that.
(*) = NB return 0 is not good practice from main() - just there to ensure the code compiles without warnings in the simplest way possible
abligh
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This works better than the above answer because you can add nex to it a new element to array without getting error. except that the octal value of double quote is 042. – LorenzKyle Mar 02 '14 at 03:05
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