C++ short* to VARIANT_BOOL*

Question

I have a function that expects a short* as an argument. I would need to convert this to a VARIANT_BOOL*. Can anybody tell me a reliable way to do this?

I can even pass the VARIANT_BOOL* to the function, but then the VARIANT_BOOL* is not filled with the correct value.

Thank you very much for the help!

STDMETHODIMP CWrapper::get_IsOpen(VARIANT_BOOL* uIsOpen, LONG* pVal)
{
    if (_c)
    {
        *pVal=_c->IsOpen(uIsOpen); //_c->IsOpen expects short* as argument
        return S_OK;
    }
    else
    {
        return S_FALSE;
    }
}

Check out [BOOL vs. VARIANT_BOOL vs. BOOLEAN vs. bool](http://blogs.msdn.com/b/oldnewthing/archive/2004/12/22/329884.aspx). — herohuyongtao, Feb 27 '14 at 12:02

score 3 · Accepted Answer · answered Feb 27 '14 at 12:01

3

VARIANT_BOOL is defined as:

typedef short VARIANT_BOOL;

So if you want to pass a VARIANT_BOOL to a function that takes a short*, you need to take its address using &. If you want turn the short that a short* points at into a VARIANT_BOOL, you need to perform indirection using *.

VARIANT_BOOL vb = VARIANT_TRUE;

short* sp = &vb; // VARIANT_BOOL to short*

VARIANT_BOOL vb2 = *sp; // short8 to VARIANT_BOOL

answered Feb 27 '14 at 12:01

Joseph Mansfield

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Thank you! I have added my code to the posting. Could you perhaps show me how I should do it exactely now that you see how I do it? – tmighty Feb 27 '14 at 12:18
@tmighty You are doing it correctly. `VARIANT_BOOL*` and `short*` are the same thing. – Joseph Mansfield Feb 27 '14 at 12:19
I had to add //VARIANT_BOOL TO BOOL *uIsOpen *= -1; to make it work correctly. – tmighty Feb 27 '14 at 12:30

score 0 · Answer 2 · answered Feb 27 '14 at 12:01

0

Put the VARIANT_BOOL in a short, call the function, put the short back into the VARIANT_BOOL.

answered Feb 27 '14 at 12:01

XTF

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C++ short* to VARIANT_BOOL*

2 Answers2