Start process with parameter

Question

You can use this command to start FreePascal from Command Prompt with a source to load: C:\FPC\2.6.2\bin\i386-win32\fp.exe 2.pas, where the first argument is the path to the FreePascal executable and 2.pas is a source. Now, I want to open sources like this from C#. I already tried this but didn't work:

Process process = new System.Diagnostics.Process();
ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.RedirectStandardInput = true;
startInfo.RedirectStandardOutput = true;
startInfo.UseShellExecute = false; //required to redirect
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = string.Format("/C C:\\FPC\\2.6.2\\bin\\i386-win32\\fp.exe \"{0}\"", sourcePath);

process.StartInfo = startInfo;
process.Start();

And

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = "C:\\FPC\\2.6.2\\bin\\i386-win32\\fp.exe";
startInfo.Arguments = path;
Process.Start(startInfo);

Do you have any suggestion? Thank you!

UPDATE Example of path value: "C:\FPC\2.6.2\bin\i386-win32\3.pas"

What's the value of `path` (in the second example - which is the right way to do it)? Does it have any spaces in it? — Matt Burland, Feb 25 '14 at 18:16
Clearly `path` contains relative path and as result file will not be opened after fixing path to exe... If it is not true - please make sure to update post with exact value of the `path`. — Alexei Levenkov, Feb 25 '14 at 18:17
http://stackoverflow.com/questions/21564532/string-format-in-c-sharp-running-command-line/21580241#21580241 — 001, Feb 25 '14 at 18:17
Updated. I tried with the S/ prefix but didn't worked. With the first block of code the window is opening, the source is loaded, but I can't interact with the program. It's like a picture. Wherever I click or press a key. — Nițu Alexandru, Feb 25 '14 at 18:32

gilly3 · Accepted Answer · 2014-02-25T18:32:25.193

4

Try adding an @ to your string, making it a verbatim string literal, so the backslashes are left alone:

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = @"C:\FPC\2.6.2\bin\i386-win32\fp.exe";
startInfo.Arguments = path;
Process.Start(startInfo);

Or:

startInfo.FileName = "cmd.exe";
startInfo.Arguments = string.Format("/C {0} \"{1}\"",
    @"C:\FPC\2.6.2\bin\i386-win32\fp.exe", sourcePath);

edited Feb 25 '14 at 18:32

answered Feb 25 '14 at 18:16

gilly3

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@Alex - If the string is good, then your question contains a typo. Backslash is the escape character. You need to either escape it (with double backslashes: `"C:\\dir"`) or use a verbatim string literal (`@"C:\dir"`). If your code accounts for that already, you should correct the code in your question. – gilly3 Feb 25 '14 at 18:37
You are right. The program has the path correctly saved and is building the path. This is the code actually. I tried to simplify for the question: startInfo.Arguments = string.Format(@"/S /C {0}\\fp.exe ""{1}""", Settings.FpcInstallationFolder.TrimEnd('\\'), path); – Nițu Alexandru Feb 25 '14 at 18:46

score 1 · Answer 2 · answered Feb 25 '14 at 18:19

1

You have to prepend the path strings with @. Please follow the code below:

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = @"C:\FPC\2.6.2\bin\i386-win32\fp.exe";
startInfo.Arguments = @"2.pas";
Process.Start(startInfo);

answered Feb 25 '14 at 18:19

Wasif Hossain

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Start process with parameter

2 Answers2