Is this an idiomatic way to convert a Guid to a Guid??
new Guid?(new Guid(myString));
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No, this is:
Guid? foo = new Guid(myString);
There's an implicit conversion from T to Nullable<T> - you don't need to do anything special. Or if you're not in a situation where the implicit conversion will work (e.g. you're trying to call a method which has overloads for both the nullable and non-nullable types), you can cast it:
(Guid?) new Guid(myString)
Jon Skeet
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Strange how Guid doesn't Parse or TryParse methods. – kͩeͣmͮpͥ ͩ Feb 04 '10 at 11:51
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2@David: They're coming in .NET 4, better late than never! http://msdn.microsoft.com/en-us/library/system.guid_members%28VS.100%29.aspx – LukeH Feb 04 '10 at 12:14
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5 years later: What? There was a time when Guids didn't have Parse or TryParse? How did you survive? I use it all the time! – C. Tewalt Sep 02 '15 at 18:48
4
just cast it: (Guid?)(new Guid(myString))
there is also an implicit cast, so this would work fine as well: Guid? g = new Guid(myString);
Grzenio
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