String tokenizer.nextToken() return value

Question

When using an if statement, for instance,

if((isInt(search1.nextToken()) == true) && search1.nextToken() != "x")

would the result returned by search1.nextToken() have different values? This is all wrapped in a while loop as well, and I'm trying to figure out what would happen.

Of course it would, you're calling `nextToken`. But this would also be trivial to verify. — Dave Newton, Feb 12 '14 at 22:26
One note on style- never say `if(something == true)`. Just say `if(something)`. — Rag, Feb 12 '14 at 22:27
@Brian Gordon why not? wouldnt you understand what I'm saying more easier? — Xavier, Feb 12 '14 at 22:42

score 1 · Answer 1 · answered Feb 12 '14 at 22:28

1

Yes, it would have different values. Whenever you do nextToken it would read the next available token. I would suggest to try with a simple java program to understand better.

answered Feb 12 '14 at 22:28

Raghu Kasturi

15
5

Hmm so for this code im testing to see if the next token is an int.. if i call the search1.nextToken inside of the if statement would it be the original token which is an int – Xavier Feb 12 '14 at 22:43
From your code I see that there are two conditions, and each search1.nextToken() expression would get different tokens. – Raghu Kasturi Apr 25 '14 at 20:54

String tokenizer.nextToken() return value

1 Answers1