Android: Exit application from custom dialog

Question

I created a custom dialog for my main activity with two buttons, Exit and Continue:

public class AgeConfirmationDialog extends Dialog {

    public AgeConfirmationDialog(Activity a) {
        super(a);    
    }

    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        requestWindowFeature(Window.FEATURE_NO_TITLE);
        setCancelable(false);
        setContentView(R.layout.age_dialog);
        // .....
        // Find the View objects; checkboxes and buttons logic; SharedPreferences
        // .....
    }
    // .....
}

This is how the dialog is launched from the MainActivity:

AgeConfirmationDialog d = new AgeConfirmationDialog(this);
d.show();

This custom dialog pops out every time the main activity is started, and asks for a age confirmation. I don't want the users to close this dialog using the back button, so I added setCancelable(false) in the onCreate method. The Continue button is disabled until a checkbox is checked. If the Continue button is pressed, the dialog is dismissed - using setOnClickListener.

The problem is that I don't know how to dismiss that custom dialog AND finish the main activity when the Exit button is pressed.

Is it possible to do this from the AgeConfirmationDialog class by setting a View.OnClickListener on the Exit button?

score 1 · Accepted Answer · answered Feb 11 '14 at 14:57

change the code to something like this:

public class AgeConfirmationDialog extends Dialog {
    Activity mainActivity;

    public AgeConfirmationDialog(Activity a) {
        super(a);    
        this.mainActivity = a;
    }

    //in onClick method of finish-button
    public void onFinishClick(View v) {
        mainActivity.finish(); //finish activity
    }
}

score 0 · Answer 2 · answered Feb 11 '14 at 14:53

0

I don't know how to dismiss that custom dialog AND finish the main activity when the Exit button is pressed.

Then you just have to put in your ExitButton Click Listener:

finish();

For example:

AlertDialog.Builder builder = new AlertDialog.Builder(this);
        builder.setPositiveButton("Exit", new DialogInterface.OnClickListener()
        {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                finish();
            }
        }).create().show();

answered Feb 11 '14 at 14:53

Sagar Shah

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And how exactly could I do this, considering that I have the AgeConfirmationDialog class that extends Dialog? – Edward Feb 11 '14 at 14:58
Not at all you just have to put my code and do just like I did. You can also see here that how I have implemented xml layout in Alert Dialog. http://stackoverflow.com/questions/21499100/how-to-show-arraylist-in-alertdialog/21508878#21508878 – Sagar Shah Feb 11 '14 at 15:03

score 0 · Answer 3 · answered Feb 11 '14 at 14:56

Do something in your onclicklistener of exit button. Like:

            Intent intent = new Intent(getApplicationContext(), MainActivity.class);
            intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            intent.putExtra("EXIT", true);
            startActivity(intent);

And your MainActivity do something like:

        if (getIntent().getBooleanExtra("EXIT", false)) {
        finish();
        }

What you basically do here is going to mainactivity which is your start activity with some key/value extra and check it in your mainactivity through getintent.

This is best process to exit application or you can use it also in logout.

Thank you! But isn't this somehow slower than Manu's version? — Edward, Feb 11 '14 at 15:06

Android: Exit application from custom dialog

3 Answers3