In this simple jaggery code
for(var i=0;i<10;i++){
print(i);
}
Output was like
0.0
1.0
....
I need to parse these outputs into integer. I tried parseInt(i) method but it also gave the same result. What could be the reason for that?
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Abimaran Kugathasan
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I think what you got is correct. JavaScript has the Number type only for numerical values. Usually you shouldn't print numbers directly. Ideally a number should be formatted before printing. i.e. You should print only after you have a string representation of the number. I'm not providing an answer as I don't have much experience with Jaggery. – Isuru Perera Feb 09 '14 at 14:19
1 Answers
0
I'm no Jaggery expert, but i have tried your code Try It tool which can be found in Jaggery Website and it gave me expected result.
The sample code i have tried is,
<html>
<body>
<h1>
<%
for(var i=0;i<10;i++){
print(i "\n");
}
%>
</h1>
</body>
</html>
Which gave me output,
0123456789
HTH,
DarRay
