Java Input from console giving unexpected values

Question

In the given code,

Input:
1
7

Output:
1

Output should be 7. What am I missing??

import java.io.*;
import java.util.*;

class compiler 
{
    public static void main(String args[] ) throws Exception 
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        int testcases = Integer.parseInt(br.readLine());

        //  System.out.println("If this statement is added it works as expected!")

        int n=Integer.parseInt(br.readLine());

        System.out.println(n);
    }
}

*I also tried using scanner

It should print 7. Strange behaviors may occur when you deal with scarce resources. Using a try-finally block and closing streams is a safer way to avoid unexpected results. — helderdarocha, Feb 08 '14 at 21:35

score 1 · Accepted Answer · answered Feb 08 '14 at 21:41

1

This should work. if you are not using an IDE, then maybe you changed your code and didn't compile again. so you are essentially running an old code with different output?

answered Feb 08 '14 at 21:41

ssayyed

766
1
8
13

It worked in Command Prompt (windows). Previously I was using IDE- JCreator. – Rajdeep Siddhapura Feb 08 '14 at 22:00
It also doesnt work in online coding contests where input is automated through stdin – Rajdeep Siddhapura Feb 08 '14 at 22:02

score 0 · Answer 2 · answered Feb 08 '14 at 21:34

0

In fact, after run your code, testcases will be 1 and n will be 7 (this will be printed on console - your example doesn't match output given).

Maybe this fragment of code will help with printing last given input to output:

int n;
while(br.readLine())
{
    n=Integer.parseInt(br.readLine());
}
System.out.println(n);

answered Feb 08 '14 at 21:34

1ac0

2,875
3
33
47

yeah, that's the problem. the example doesn't match the output – Rajdeep Siddhapura Feb 08 '14 at 21:37
in that case, you are running another code or copying output from another console ;) – 1ac0 Feb 08 '14 at 21:38

score -3 · Answer 3 · answered Feb 08 '14 at 21:31

-3

 The code must be like this if you want to use command line argument
 Public static void main(String ar[])
 {

  int i=(0;
  for(i=0;i<ar.length;i++)
  System.out.println(" "+ar[i]);

    }

answered Feb 08 '14 at 21:31

user3288136

1

This is not related to the question. It could be a comment. – Christian Tapia Feb 08 '14 at 21:32
This code wont work. It has several syntax errors. – helderdarocha Feb 08 '14 at 21:33
I know ..public will be in small and i=0;...those writting mistakes – user3288136 Feb 08 '14 at 21:37

Java Input from console giving unexpected values

3 Answers3