Creating a unique index for a collection in reactivemongo

Question

Looking at the MongoDB documentation it looks like you can ensure an index is created for a collection at application runtime using a command that looks something like this:

db.myCollection.ensureIndex({'my-col': 1}, {unique: true})

I can't find anything like this in the reactive mongo apis. Does such a thing exist?

score 7 · Accepted Answer · edited Jan 21 '19 at 05:27

7

You can access the IndexManager from your BSONCollection:

collection.indexesManager.ensure(...)

See reactivemongo docs for details:

0.9 (as of Jan 2019 - gives 404)
0.1x (as of Jan 2019 - current version)

edited Jan 21 '19 at 05:27

J0HN

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answered Jan 25 '14 at 18:24

vptheron

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please mention one sample for creating index and also for remove index using reactive-mongo – Harmeet Singh Taara Nov 19 '15 at 11:13
link is not valid – mfudi Jun 08 '18 at 07:34

score 0 · Answer 2 · answered Jul 13 '20 at 06:42

As of libraryDependencies += "org.reactivemongo" %% "play2-reactivemongo" % "0.20.3-play28"

1st define the index

val createdTSInx = Index(
  key = Seq("createdTS" -> IndexType.Ascending),
  name = Some("createdTSInx"),
  unique = true,
  background = false,
  sparse = false,
  expireAfterSeconds = None,
  storageEngine = None,
  weights = None,
  defaultLanguage = None,
  languageOverride = None,
  textIndexVersion = None,
  sphereIndexVersion = None,
  bits = None,
  min = None,
  max = None,
  bucketSize = None,
  collation = None,
  wildcardProjection = None,
  version = None,
  partialFilter = None,
  options = BSONDocument.empty)

// to create

  collection.indexesManager.create(createdTSInx)

//to ensure

  collection.indexesManager.ensure(createdTSInx)

Creating a unique index for a collection in reactivemongo

2 Answers2