I was asked this question in an interview to improve the code that was provided. The provided code used lot of if statements and therefore I decided to use HashMap
as retrieval would be faster. Unfortunately, I was not selected for the position. I am wondering if someone knows a better way than what I did to improve the code?
/* The following Java code is responsible for creating an HTML "SELECT" list of
U.S. states, allowing a user to specify his or her state. This might be used,
for instance, on a credit card transaction screen.
Please rewrite this code to be "better". Submit your replacement code, and
please also submit a few brief comments explaining why you think your code
is better than the sample. (For brevity, this sample works for only 5
states. The real version would need to work for all 50 states. But it is
fine if your rewrite shows only the 5 states here.)
*/
/* Generates an HTML select list that can be used to select a specific U.S.
state.
*/
public class StateUtils {
public static String createStateSelectList() {
return
"<select name=\"state\">\n"
+ "<option value=\"Alabama\">Alabama</option>\n"
+ "<option value=\"Alaska\">Alaska</option>\n"
+ "<option value=\"Arizona\">Arizona</option>\n"
+ "<option value=\"Arkansas\">Arkansas</option>\n"
+ "<option value=\"California\">California</option>\n"
// more states here
+ "</select>\n"
;
}
/* Parses the state from an HTML form submission, converting it to the
two-letter abbreviation. We need to store the two-letter abbreviation
in our database.
*/
public static String parseSelectedState(String s) {
if (s.equals("Alabama")) { return "AL"; }
if (s.equals("Alaska")) { return "AK"; }
if (s.equals("Arizona")) { return "AZ"; }
if (s.equals("Arkansas")) { return "AR"; }
if (s.equals("California")) { return "CA"; }
// more states here
}
/* Displays the full name of the state specified by the two-letter code. */
public static String displayStateFullName(String abbr) {
{
if (abbr.equals("AL")) { return "Alabama"; }
if (abbr.equals("AK")) { return "Alaska"; }
if (abbr.equals("AZ")) { return "Arizona"; }
if (abbr.equals("AR")) { return "Arkansas"; }
if (abbr.equals("CA")) { return "California"; }
// more states here
}
}
My solution
/* Replacing the various "if" conditions with Hashmap<key, value> combination
will make the look-up in a constant time while using the if condition
look-up time will depend on the number of if conditions.
*/
import java.util.HashMap;
public class StateUtils {
/* Generates an HTML select list that can be used to select a specific U.S.
state.
*/
public static String createStateSelectList() {
return "<select name=\"state\">\n"
+ "<option value=\"Alabama\">Alabama</option>\n"
+ "<option value=\"Alaska\">Alaska</option>\n"
+ "<option value=\"Arizona\">Arizona</option>\n"
+ "<option value=\"Arkansas\">Arkansas</option>\n"
+ "<option value=\"California\">California</option>\n"
// more states here
+ "</select>\n";
}
/* Parses the state from an HTML form submission, converting it to the
two-letter abbreviation. We need to store the two-letter abbreviation
in our database.
*/
public static String parseSelectedState(String s) {
HashMap<String, String> map = new HashMap<String, String>();
map.put("Alabama", "AL");
map.put("Alaska", "AK");
map.put("Arizona", "AZ");
map.put("Arkansas", "AR");
map.put("California", "CA");
// more states here
String abbr = map.get(s);
return abbr;
}
/* Displays the full name of the state specified by the two-letter code. */
public static String displayStateFullName(String abbr) {
{
HashMap<String, String> map2 = new HashMap<String, String>();
map2.put("AL", "Alabama");
map2.put("AK", "Alaska");
map2.put("AZ", "Arizona");
map2.put("AR", "Arkansas");
map2.put("CA", "California");
// more state abbreviations here here
String full_name = map2.get(abbr);
return full_name;
}
}
}